I have a Casio watch that has two simultaneous displays: a large, analog display (with physical hour and minute hands, but no seconds hand); and a smaller LCD window with a digital display that can be switched to various modes.
Since I normally keep the LCD in "show today's date" mode, and there's no seconds hand, there's usually no visible movement. But sometimes I switch the LCD to the Timer (stopwatch) mode, and then the hundredths of seconds and seconds flash past in a continuous moving display. I can keep the timer running in the background while switching back to a static display (such as the date), but I prefer to keep the timer visible when it's running.
Here's my question: Is the drain on the watch battery greater when there's visible movement in the LCD portion of the display? Or does an LCD displaying a static image consume the same amount of power as that same LCD when displaying a moving image? (I suppose there might even be an additional question as to whether the watch's microprocessor consumes more power when keeping the stopwatch-timer running, in addition to the regular time function that must always be running.)
Thanks much for any enlightenment.