Timer 2 overflow = interrupt 5?

Question

Hi there..Getting timer 2 to signal an interrupt using C code was a bigger task than Iexpected. This is the code that seems to work, but I don't have any clue onwhy it works - perhaps someone here can point me in the correct direction?When I look in the documentation to the 80c535 it mentions that interrupt 5is tied to the CC2 / P1.2. When you look at the code you'll discover I don'ttouch the register/pin at all.#include #include void timer2(void) interrupt 5{ TF2 = 0;}void main(){ TH2 = 0xff;   // timer 2 high byte TL2 = 0x50;   // timer 2 low byte EAL = 1;    // enables global interrupt thingy ET2 = 1;    // yup to timer 2 interrupt CRCH = 0xff; CRCL = 0x50; T2CON = 0x11;  // boots the timer while (1) { }}Thanks in advance!-- I doubt, therefore I might be.

Gary Kato · Accepted Answer

INT 5 is probably used for timer overflow if  timer 2 is enabled and triggeredby P1.2 if timer 2 is not enabled. Lots of pins on microcontrollers are dualmode.

Kim Noer · Answer

But the problem I have is that the documentation doesn't mention this, it does mention that a timer 2 can generate an interrupt - but it sneaks around explaining exactly what interrupt it uses..

CBarn24050 · Answer

Hi, if you look in the manual under "interrupt structure" you should find alist of what sources each interrupt. It's too important not be listedsomewhere.

Timer 2 overflow = interrupt 5?

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