Hi folks-
I think my brain is blocked and google isn't showing any solutions:
Does anyone know of a way in C code to get the base 10 integer exponent of a single precision float?
Thanks, John.
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log10(x) ?
I'm not sure what you are getting at :< (perhaps parentheses in your question would make it clearer :> )
I.e., do you want the exponent field of the float expressed as a decimal integer? For example:
int exponent; double fraction = frexp((double) x, int &exponent); print("The exponent is %d.\n", exponent);
Could you represent your float algebraically in terms of the quantity you are after to be more clear? I.e., for the above:
x = fraction * (2 ** exponent)
(more or less)
floor(log10(x))
Thanks, Tim. That worked! I knew it was something simple.
JJS
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