LC, the
frequency.
bottom side
j50 and
Voltage or 50
I think you mean 50Vrms with 1 ohm output impedance :-)
Current = Voltage / Impedance
I = 50 / (1 + j50 - j50) = 50/1 = 50 Amps RMS
Voltage = Current * Impedance
Voltage across capacitor = 50 * -j50 = -j2500
i.e. 2500V RMS 90 degrees out of phase with the current.
The voltage across the inductor is the same magnitude, but 90 degrees out of phase the other way (+j2500)
The voltages across L and C are 180 degrees w.r.t each other - so they cancel.