Question about Modelling the ESR of a Capacitor

Apr 06, 2007 3 Replies

Hi Guys,



under:



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you can find some basics about the 'ESR' of a Capacitor.



A formula is shown describing the 'ESR' as: Rp/((2*Pi*f*Cp*Rp)^2+1) and the 'ESC' is : Cp+1/((2*Pi*f*Rp)^2*Cp)


I guess, that the basic model looks like this:



|| __________ __________



--------o----------||--------o-----|__________|-------|==========|---- | || Cp | Rs Ls | ___________ | |---|___________|----| Rp


My first Questions:



Is the formula for the ESR correct?? Paralleling Cp and Rp should result into an impedance of: Rp/sqrt(1+(2*Pi*f*R*C)^2)



Or NOT????


My second Question:



I don't have a glue how the 'ESC' has to be calculated at all. What is the idea behind that?


So long


Karsten


ESR = Rs.

I have no idea what ESC stands for.

Avoid tantalums. They tend to explode.

John

"K2"

** The formulae applies to fig 4 which shows a perfect capacitor in parallel with a resistor.
** No.

Fig 4 does not show what you drew.

** For the case shown in of fig 4 only.

** To make the parallel and serie scircuits bahave the same at the frequency of interest.

Same impedance and same phase angle.

....... Phil

some beginning of the answer... :

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regards,

Jean-Yves.

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