I was just wondering why RF power sensors designed for power meters are so much more expensive than integrated circuits that measure RF power. The former seem to be several thousand dollars while the latter seem to be several dollars. Any information is appreciated.
Thank you.
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M
Michael A. Terrell
Show me an IC that will measure 500 watts of broadband RF, and can meet the required metrology requirements.
Service to my country? Been there, Done that, and I\'ve got my DD214 to
prove it.
Member of DAV #85.
Michael A. Terrell
Central Florida
J
jasen
LT1088: 2% at 100 Mhz - you'll need to shunt most of those watts.
it may be possible to add a compensation network and get even better performance,
Bye. Jasen
M
Michael A. Terrell
First of all, you can't "Use a shunt" for RF power measurements. You have to use a power attenuator if the sensor has a 50 ohm input. If its high impedance, you use a voltage divider after the termination, but it still isn't a certified power sensor. Without a specific calibration procedure and being certified by a metrology lab with traceable references, its only a hobby grade toy.
Service to my country? Been there, Done that, and I\'ve got my DD214 to
prove it.
Member of DAV #85.
Michael A. Terrell
Central Florida
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