# How do you calculate voltage peaks after a tube full-wave rectifier?

• posted

The voltage drop through a tube rectifier under light load is practically zero.

• posted

"at" schreef in bericht news:cgsn6g\$onj\$ snipped-for-privacy@nyytiset.pp.htv.fi...

full-wave

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According to the datasheet

the peak voltage depends on the current. If you have no or a very small load, the peak voltage will be about 1.41 * Vin. Vin being the RMS value of a sine wave AC source. The current will highly depend on the load and the smoothing filter. This and the accurancy of the tube parameters make a general calculation scheme less usefull. (Although you can make one if you want.)

petrus bitbyter

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• posted

How do you calculate the voltage peaks of voltage coming out of a full-wave rectifier tube?

If 230V 50Hz AC has voltage peaks approx 1.41 times the average voltage, the voltage peaks seen by the rectifier tube would also be like that. But what happens in the rectifier? How high are the peaks coming out of it? The rectifier in question is a GZ34 tube, and it has a voltage multiplier of

1.3, so output voltage (DC) is 1.3 times input voltage (AC), so if 230VAC average goes in, the output is 299 average. But how high are the voltage peaks that come out of the tube?

Thanks!

-at

• posted

Hi,

This should give you sufficient information to work it out for your particular set of circumstances -

Cheers - Joe

• posted

"How do you calculate voltage peaks after a tube full-wave rectifier?"

Just run some spice simulations. It will take you < 1sec per run.

Hint: SuperSpice has the GZ34 tube model and a symbol for it.

Kevin Aylward snipped-for-privacy@anasoft.co.uk

SuperSpice, a very affordable Mixed-Mode Windows Simulator with Schematic Capture, Waveform Display, FFT's and Filter Design.

• posted

Thanks.

This will help.

-at

full-wave

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