I need about 5% duty cycle pulse of about 1 sec time period. A second pulse required should be of same characteristics but delayed by a duration by about the 'on' time of the second pulse. ie the first pulse should go on and then the secoond pulse should go on. Need a simple solution please
generating pulse
Jun 23, 2006
3 Replies
Cheapest is a microcontroller running on its internal RC oscillator, which you may have more or less calibrated.
If you don't want to use microcontrollers, you can use a 1 Hz oscillator that feeds a monostable that generates 50 ms wide, high logic-level pulses. A second monostable is set to trigger on the high-to-low transitions of the first monostable's output, and also generates 50 ms wide, high logic-level pulses. You can do the whole thing with a 40106 (hex inverter with schmitt-trigger), three capacitors, three resistors and two diodes, as shown in the figure.
http://80.35.195.131/ng/ng_20060623A01.png
R1 & C1 such that period is 1 s. R2 & C2 such that A and B pulses are 50 ms wide. D1 can be 1N4148.
Best,
So, you want: ___ Trig ___| . . . (doesn't matter?) __________ A ___| |________________ . . . (until next trigger) __________ B ______________| |_____ . . .
???
You can do that with two of these.
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Trig is the input. Connect Q' (Q bar) to Trig of the second one. Use Q from each for the "A" and "B" output above. Adjust Rt and Ct for one second.
Tim
-- Deep Fryer: a very philosophical monk. Website:
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_ _ _ _ | | | | | | | |
-- -- --------------------- -- --- T 0 1 2 3 Repeat
So you want T0-T1 = 50 mS, T1-T2 = 50mS, T0-Repeat = 1000 mS?
Count to 20 in 50 mS steps (drive 4017's with a 555 running at 20 hZ, set the 4017 chain to reset at count 20). Use counter output 0 and
2 for your pulses. Actually you can use any pair of counts such that there is one count between them, like 1 and 3, 2 and 4, 3 and 5, etc.Ed
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