generating pulse

I need about 5% duty cycle pulse of about 1 sec time period. A second pulse required should be of same characteristics but delayed by a duration by about the 'on' time of the second pulse. ie the first pulse should go on and then the secoond pulse should go on. Need a simple solution please

Reply to
prateek
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Cheapest is a microcontroller running on its internal RC oscillator, which you may have more or less calibrated.

If you don't want to use microcontrollers, you can use a 1 Hz oscillator that feeds a monostable that generates 50 ms wide, high logic-level pulses. A second monostable is set to trigger on the high-to-low transitions of the first monostable's output, and also generates 50 ms wide, high logic-level pulses. You can do the whole thing with a 40106 (hex inverter with schmitt-trigger), three capacitors, three resistors and two diodes, as shown in the figure.

http://80.35.195.131/ng/ng_20060623A01.png

R1 & C1 such that period is 1 s. R2 & C2 such that A and B pulses are 50 ms wide. D1 can be 1N4148.

Best,

Reply to
Mochuelo

So, you want: ___ Trig ___| . . . (doesn't matter?) __________ A ___| |________________ . . . (until next trigger) __________ B ______________| |_____ . . .

???

You can do that with two of these.

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Trig is the input. Connect Q' (Q bar) to Trig of the second one. Use Q from each for the "A" and "B" output above. Adjust Rt and Ct for one second.

Tim

-- Deep Fryer: a very philosophical monk. Website:

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Reply to
Tim Williams

_ _ _ _ | | | | | | | |

-- -- --------------------- -- --- T 0 1 2 3 Repeat

So you want T0-T1 = 50 mS, T1-T2 = 50mS, T0-Repeat = 1000 mS?

Count to 20 in 50 mS steps (drive 4017's with a 555 running at 20 hZ, set the 4017 chain to reset at count 20). Use counter output 0 and

2 for your pulses. Actually you can use any pair of counts such that there is one count between them, like 1 and 3, 2 and 4, 3 and 5, etc.

Ed

Reply to
ehsjr

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