It doesn't help that rectifier ratings are by average current passed through a whole cycle. A nominal '1A' rectifier (1N4003) will be OK with 10A (nonrepetitive) during startup, and 2A output current in a fullwave bridge (because it has only 50% duty cycle) and that amounts to 1A average, but is also 2.8 A peak, and 1.4A RMS.
Then there's the problem of overrated components (low ESR capacitors and low series resistance rectifiers and oversize copper windings) causing excessive startup currents. You might need to add NTC or other resistive elements if your capacitors, windings, and rectifiers have been overrated improperly. I shudder to recollect some of the attempts of golden-eared audiophiles to redo power supply components according to vague ideas like 'properly overrating'.
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J
John Larkin
Problem is, it will also follow the significant ripple on its collector.
P
Phil Hobbs
Nah, that's a capacitance multiplier. As long as you don't let it saturate, it's the bomb for supply rejection.
Cheers
Phil Hobbs
Dr Philip C D Hobbs
Principal Consultant
ElectroOptical Innovations LLC
Optics, Electro-optics, Photonics, Analog Electronics
160 North State Road #203
Briarcliff Manor NY 10510
hobbs at electrooptical dot net
http://electrooptical.net
M
Maynard A. Philbrook Jr.
That still does not remove the ripple from the caps, what the F is wrong with you? I understand Phil better now.
Jamie
M
mroberds
Quick version: I am almost certain John is talking about the DC *on C1 and C2*, not the DC at the output of the supply.
Long version...
There will *always* be some ripple "before" the LM317 - across C1 and C2 in the diagram you posted.* If you had a transformer with a 24 V AC secondary, and you were drawing 1 A (DC) from the output of the power supply, and you put an oscilloscope probe across C2, you'd see a DC voltage varying between about 30 V and 32 V DC. The variation would be at 120 Hz. You can reduce the amount of this ripple by making C1 and C2 bigger, but you can never get it to go away completely.
(* From "Getting Started in Electronics" by Forrest Mims, I think.)
There will be *much less* ripple "after" the LM317 - across C3 - as long as you have R1 adjusted to give an output voltage less than about 27 V (in this example). If you put an oscilloscope probe across C3, you'd see a DC voltage varying between (say) 27.000 V and 27.005 V. You can reduce this ripple a little by putting another capacitor across R1 - see the LM317 data sheet. A lot of things you would run from this power supply won't care about this. Audio stuff might care a little (you might hear a 120 Hz hum in the audio), depending on the audio voltage levels you are using.
The main reason you have to care about the ripple "before" the LM317 is that it effectively sets the highest output voltage you can get from the supply. There will always be a couple of volts of drop "through" the LM317 - in other words, even if you set the ADJ pin for maximum output, the OUT pin will always be a couple of volts less than the IN pin.
If the voltage on C1 and C2 is rippling between 30 V and 32 V, and you set R1 for 27 V output or less, then there is always at least 3 V available to lose in the LM317, and the output will be stable at 27 V. If you tried to turn up R1 to get 29 V on the output, there would only be between 1 and 3 V available to lose in the LM317. 1 V isn't enough for the LM317, so part of the time, you wouldn't get the full 29 V on the output.
There is an article by Don Lancaster on how to pick the filter capacitor size on PDF page 104 of
formatting link
. In that article, Figure 1-B is you, the capacitor is the combination of C1 and C2 in your schematic, and the resistor represents your LM317 and everything "after" it.
Matt Roberds
J
John Fields
Indeed.
But then there's always active soft-start...
John Fields
J
John Fields
From the caps???
Of course not, silly boy; I thought you were talking about the
supply's regulated output.
I
Ian Field
So far I don't recall ever having seen a PTC in front of a transformer PSU.
Over the past year or so my web trawling has dredged up all manner of weird and wonderful arrangements - most often a relay to switch a resistor in/out of the primary feed, the variety is in the circuits controlling the relay.
J
John Fields
With good reason; a PTC's resistance increases when it heats up.
John Fields
I
Ian Field
OOPS! - typo - that should read NTC.
J
John Larkin
Sure, as long as the input ripple is small, a few tenths p-p. But the suggestion was to put the c-multiplier between the bridge+filter caps and the main linear regulator, where one might expect amps of current and volts of ripple.
John Larkin Highland Technology, Inc
jlarkin att highlandtechnology dott com
http://www.highlandtechnology.com
J
John Larkin
The full solution involves the copper loss and the leakage inductance of the transformer, the diode characteristics, the capacitance and ESR of the filter capacitors, and maybe the impedance of the AC power line. All that is easier to Spice, or just to test, than to calculate.
John Larkin Highland Technology, Inc
jlarkin att highlandtechnology dott com
http://www.highlandtechnology.com
J
John Larkin
Don's math is pessimistic, because it assumes that the cap is charged instantaneously and discharges for a full half cycle. A real sine wave is mostly flat on top, so the cap doesn't discharge for 8.333 msec.
John Larkin Highland Technology, Inc
jlarkin att highlandtechnology dott com
http://www.highlandtechnology.com
P
Phil Hobbs
Lately I've been using shunt regulators on the base string of cap multipliers. AFAICT the best is the Exar SPX431A. You can adjust that to lop off the ripple if you like, though of course it isn't as efficient as using a huge cap.
Cheers
Phil Hobbs
Dr Philip C D Hobbs
Principal Consultant
ElectroOptical Innovations LLC
Optics, Electro-optics, Photonics, Analog Electronics
160 North State Road #203
Briarcliff Manor NY 10510
hobbs at electrooptical dot net
http://electrooptical.net
G
George Herold
That's interesting, the Exar is "best" because it has the least noise to start with?
As you've said, the reference/regulator can be the noisiest part of a design. I've got an LT3080 in an instrument. (cap multiplier after it.) And I've regretted it. Much better to just make your own, (reference->opamp->transistor)
George H.
P
Phil Hobbs
The Exar is quieter and has a lower minimum cathode current.
0-------*---------RRRR---*---* *-*----------0 | | \ / | R | \ A | R | ------ | R CCC | | R CCC R | | | R R | GND R R | R R | | R | | | *---RRRR---*--RRRR------* | | | | | | | | | CCC /---/ CCC | CCC / \---* CCC *--RRRR--* | --- | | | | GND | | GND | GND | | | GND *-------------*
Cheers
Phil Hobbs
Dr Philip C D Hobbs
Principal Consultant
ElectroOptical Innovations LLC
Optics, Electro-optics, Photonics, Analog Electronics
160 North State Road #203
Briarcliff Manor NY 10510
hobbs at electrooptical dot net
http://electrooptical.net
J
John Larkin
That circuit necessarily increases Vce, which has additional benefits.
Lots of circuits have good supply rejection at low frequencies and need help at high frequencies. In those cases, just RC power filtering works well. Polymer aluminum caps are great for that.
I've also done closed-loop opamp regulators with a huge RC tau on the output. That lops off the HF part of the noise.
John Larkin Highland Technology, Inc
jlarkin att highlandtechnology dott com
http://www.highlandtechnology.com
I
Ian Field
Who suggested that then - I never even mentioned the bridge and filter caps.
G
George Herold
Nice, I like that you've got the cap multiplier inside the feedback path.
Thanks, George H.
W
whit3rd
It's possible to get lower (SPX431A wants over 400 uA, and TLV431 wants over 50 uA) but there's some cathode-voltage-range issues, too.
Have you considered direct shunt regulation?
0--------*---RRRR---*-----*----------0
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