Viewing ohms change on oscope???

Hello, I'm looking for a circuit I can build or equipment I can buy so I can time how long an ohms change is. I would like to build it if possible . I would like to view it on a scope. One example would be a starting ohms reading from a device of 1355 ohms. It will increase by approx. 20 ohms and then return to 1355 ohms. The time it will take is approx. 19 seconds. I will need to be able to see a change as small as 1 ohm if possible , but the most important thing is to see the reading change from 1355 and return to

1355 ohms. I need to then measure the time with cursers on a scope. I know a respiration monitor can see and display an ohms change , but I need a way to exactly measure the change. I will be greatful for any help. Thank you, Jeff
Reply to
scanner80
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Build or buy a precision current source to source 1mA, then use a multimeter. My cheapo sears multimeter can resolve 1 mV, and it only cost $30.

A fairly reasonable current source can be made with a TL431. Use a 1%

2.49k resistor from ref to anode, put your thingy from ref to cathode, then connect a 1k resistor to a 5V source. Your ohms output is then 1000
  • V(cathode) - 2500.
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Regards,
  Bob Monsen

If a little knowledge is dangerous, where is the man who has
so much as to be out of danger?
                                  Thomas Henry Huxley, 1877
Reply to
Bob Monsen

You can make a window comparator that puts out a logic 1 if the input voltage is within a certain range. The resistor under test can be supplied by a precision current source to produce a voltage signal. Or, if the comparator reference voltage divider and your resistor are driven from the same voltage source and precision resistors are used, a supply with reasonably stable voltage regulation will suffice.

The comparator output can drive a simple timer circuit, or an LED if stopwatch precision will suffice.

--
Paul Hovnanian     mailto:Paul@Hovnanian.com
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I bet the human brain is a kludge. -- Marvin Minsky
Reply to
Paul Hovnanian P.E.

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Reply to
scanner80

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Reply to
scanner80

The device may have some kind of current limit, but 1 mA probably wont be a problem.

If you are afraid of higher currents, you'll probably have to amplify the resulting voltage. Use the following or something similar so as not to disturb the voltage across the device too badly:

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A 100x amplifier will give you good results with 10uA. You could also use a sample and hold circuit to match the voltage before the test, and do a comparative measurement between the two during the test. That way, you can amplify 1000x or even 10000x, since you will only be amplifying the change, which should be less than 200uV at 10uA.

There is an autonulling dc lab amplifier schematic in Art of Electronics, second edition that might be perfect (perhaps a more than you really need...) for your application. The schematic is Figure 7.1 on page 393. Set the gain, null it out, and start the test.

--
Regards,
  Bob Monsen

If a little knowledge is dangerous, where is the man who has
so much as to be out of danger?
                                  Thomas Henry Huxley, 1877
Reply to
Bob Monsen

The quick way to do this is to use a 9-volt battery or two and make a

4-resistor wheatstone bridge, with your test resistor as one of the legs, and go directly into the scope. Crank up scope gain as required. You may need to hang a big capacitor across the scope input if you pick up too much hum.

Refinements: a zero-null pot, and a switchable 10-ohm cal check resistor.

John

Reply to
John Larkin

You can almost make this into a Radio Shack project using the circuit below- the only matching required is on the two 1% 12.4K ohms resistors. As shown, the circuit will produce slightly less than 1mV per ohm change in your 1355 RUT to within a few percentage points, and you can gain this up as required. Adjust Rpot for Vout=0V while RUT is in quiescent state. View in a fixed-width font such as Courier.

. . +----------+--------+ . | + | | . | | --- . | Vref | /// V+ . | [12.4k] | . _|_ - | U1:B | . / \\---------+---------------------|+\\ . --- LM385 | | >--+-> Vout . | Q2 e +---|-/ | . | |/ | | | . | Q1 e---| 2x PN4250A | | | . | |/ |\\ | V- | . +--| c | | . | |\\ | +-[12.4k]-+ . | c | | . | | | U1:A Q3 c . | +-----+--------|+\\ |/ . | | | >---| Vref . [100k] || +--|-/ |\\ Vout= ---- x d(RUT) . | 100uA|| | e RUTo . | v| | | . | | +-----------+ _ . | | | /| . | [RUT] [Rpot] . | | /| . | (1355)| | . | | | . +----------+-----------------+ . | . --- . V- . .

Reply to
Fred Bloggs

That would be a dual single-supply OA running off +/-5 or so, low offset type preferable, Q3 is high gain.

Reply to
Fred Bloggs

Here is how you can gain that sensor ohm change by x10 with T-feedback around the output difference amplifier. It may not look like it, but this is a bridge. The "cal" switch is either an NC momentary or a jumper strap, open it and record the change in Vout to get the exact gain constant. Do this after you zero the output with Rpot. Rpot will be adjusted to be equal R.U.T. within 1-2% for zero, so you figure out the range you need. View in a fixed-width font such as Courier.

. . +----------+--------+ . | + | | . | | --- . | Vref | /// V+ . | [12.4k] | . _|_ - | U1:B | Vout . / \\---------+-------[12.4k]-------|+\\ . --- LM385 | | >--+-> 10mV/OHM . | Q2 e +---|-/ | . | |/ | | | . | Q1 e---| 2x PN4250A | | [68.1k] . | |/ |\\ | V- | . +--| c | | . | |\\ | +-[6.19k]-+ . | c | | | . | | | U1:A Q3 c [6.81k] . | +-----+--------|+\\ |/ | . | | | | >---| 2N5962 --- . |cal o| | +--|-/ |\\ /// . | --+ [10] | e . | o| | | | . | | | | | . | +-----+ +-----------+ . [100k] | | . | || | U1=LT1013 . | 100uA|| | _ . | v| | /| . | | [Rpot] . | [RUT] /| . | | | . | (1355)| | . | | | . +----------+-----------------+ . | . --- . V- .

Reply to
Fred Bloggs

Not sure if I'm missing something here - what's wrong with a 'meter with IEEE-488 bus and a PC so-equipped. Takes a few minutes to write the program with HPIV or VB and you can graphically display it. Alternative is to use a higher-end Fluke or similar with RS-232 bus. The rate at which you can read and precision of the reading is then a function of how much you spend on the meter.

Ken

Reply to
Ken Taylor

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