Turning on a MOSFET from 0-5V

Consider this circuit:

____ 12V VCC | | + | | | | | | \\/ | | | | |< .-. |----| | | | |\\ | | | | '-' | | | .-. | | | | | ||-+ | | | ||

Reply to
leo2100
Loading thread data ...

That sounds like an arbitrary set of requirements. Homework?

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com

Posting from Google?  See http://cfaj.freeshell.org/google/

"Applied Control Theory for Embedded Systems" came out in April.
See details at http://www.wescottdesign.com/actfes/actfes.html
Reply to
Tim Wescott

There's nothing in the circuit to ever pull the gate low.

Homework?

John

Reply to
John Larkin

Tim Wescott ha escrito:

Kind of homework, I shouldn't take this problems home but I'm interested so I do, at least while the euphoria lasts. The arbitrary part is mine, any ideas on how to make the requirements more down-to-earth ?

Reply to
leo2100

John Larkin ha escrito:

I thought that if the input reached 12V, it should cut off the Collector current, but now that I think about it, the smallest leakeage current should drive the MOSFETs gate high. SO I`m left without nothing :)

Here's Homework: State the difference between a chat and 1 min. apart USENET posts.

Reply to
leo2100

You don't want to leave the BE of the bipolar floating either.

Tam

Reply to
Tam/WB2TT

What do you mean by 'invert the logic'? Is the MOSFET to be on or off for a +5V input? I mean, is the output seen as the load current or the drain voltage?

-- John

Reply to
John O'Flaherty

Why not use an NPN, with a resistor from collector to +12V, and the collector connected to the MOSFET gate? Still inverting, but it'll work.

Or toss the BJT entirely and use a logic-level MOSFET.

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com

Posting from Google?  See http://cfaj.freeshell.org/google/

"Applied Control Theory for Embedded Systems" came out in April.
See details at http://www.wescottdesign.com/actfes/actfes.html
Reply to
Tim Wescott

John O'Flaherty ha escrito:

5V Input ---> MOSFET ON 0V Input ---> MOSFET OFF

The goal of the circuit is to switch the MOSFET ON and OFF, the VDS voltage is already taken care of so it will work like a voltage controlled resistor (VGS=12V)

Reply to
leo2100

Tim Wescott ha escrito:

The NPN switch is discarded because it inverts the logic.

I was told that I should not use the output of the logic circuit (CD4555 Output) because it might couple noise to the signal's path (that is the drain-source channel) without a proper RC Lowpass filter and still with the RC and all, it wasn`t advisable.

Reply to
leo2100

OK, I feel sorry for you: Common-base NPN transistor and 2 resistors.

John

Reply to
John Larkin

Hello Leo,

I'll second that. Or use CD4000 series logic to drive it. If it has to be fast add a npn/pnp pair as push-pull.

What noise?

--
Regards, Joerg

http://www.analogconsultants.com
Reply to
Joerg

Yep. I think we need to quit solving the homework and send Leo over to basics ;-)

...Jim Thompson

--
|  James E.Thompson, P.E.                           |    mens     |
|  Analog Innovations, Inc.                         |     et      |
|  Analog/Mixed-Signal ASIC\'s and Discrete Systems  |    manus    |
|  Phoenix, Arizona            Voice:(480)460-2350  |             |
|  E-mail Address at Website     Fax:(480)460-2142  |  Brass Rat  |
|       http://www.analog-innovations.com           |    1962     |
             
I love to cook with wine.      Sometimes I even put it in the food.
Reply to
Jim Thompson

(Boylestad-Nashelsky

NPN's.

against

ground)

The

to

to

not

work.

If you want to use a single bjt non inverting amplifiying stage it has to be common base, ie an npn with the base conected to 5v via a resistor, emitter goes to logic output, colector goes to mosfet gate and pulled upto 12v however this is realy rather a poor circuit as it does not provide the isolation you seem to think you need.

TBH you need to rethink the requirments.

COlin =^.^=

Reply to
colin

[snip]

Solution shown at....

formatting link

{:-)

...Jim Thompson

--
|  James E.Thompson, P.E.                           |    mens     |
|  Analog Innovations, Inc.                         |     et      |
|  Analog/Mixed-Signal ASIC\'s and Discrete Systems  |    manus    |
|  Phoenix, Arizona            Voice:(480)460-2350  |             |
|  E-mail Address at Website     Fax:(480)460-2142  |  Brass Rat  |
|       http://www.analog-innovations.com           |    1962     |
             
I love to cook with wine.      Sometimes I even put it in the food.
Reply to
Jim Thompson

Or use a 74HCxx non-inverting buffer ('06?), or a 74HC04 with one gate driving another (or the other five) for non-inverting operation. If you _really_ need speed you can wire all the outputs in parallel through small resistors. You won't get up to ultra-fast switcher speeds, but you'll get pretty fast, and in not much more space than you'd use for discrete transistor solutions.

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com

Posting from Google?  See http://cfaj.freeshell.org/google/

"Applied Control Theory for Embedded Systems" came out in April.
See details at http://www.wescottdesign.com/actfes/actfes.html
Reply to
Tim Wescott

Jim Thompson ha escrito:

OH !!! THE BYTES !!!! THE BANDWIDTH !!!

Batteries sold separately ?

;)

Thanks everyone, I think I`m gonna try to use the logic output (if there actually is a discrete Enhacement MOSFET in this damned city) , like they say if it ain`t broken ... Thank's for the Common-Base circuit, I neglected it completely.

Reply to
leo2100

"Jim Thompson" wrote in message news: snipped-for-privacy@4ax.com...

and a bi-directional version

formatting link

Ian

Reply to
IanM

You were going to explain to us how this circuit can turn off? You've now realized that you need a 12V logic swing to turn off the PNP but once that's off, how does the MOSFET's gate capacitor get discharged from its nice 12V turned-on voltage?

Here's how to do it. All the resistors can have the same value, say 2.2k ohms. Study the circuit and tell us what the operating limits are for the high-voltage bus. You can make this circuit work to very high variable voltages by adding one more resistor. See if you can tell us where that part goes.

. -----+------+-------+---- . | | | . R1 | | . | |< .-. . +----| | | . | |\\ | | . | | '-' LOAD . |/ | | . 0 or 5V logic -----| | |--' . |\\v | ||

Reply to
Winfield Hill

[snip]

That's really crappy. In the real world this is quite nicely (and speedily) done in CMOS chips.

...Jim Thompson

--
|  James E.Thompson, P.E.                           |    mens     |
|  Analog Innovations, Inc.                         |     et      |
|  Analog/Mixed-Signal ASIC\'s and Discrete Systems  |    manus    |
|  Phoenix, Arizona            Voice:(480)460-2350  |             |
|  E-mail Address at Website     Fax:(480)460-2142  |  Brass Rat  |
|       http://www.analog-innovations.com           |    1962     |
             
I love to cook with wine.      Sometimes I even put it in the food.
Reply to
Jim Thompson

ElectronDepot website is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.