Revisit amps input impedance

First, look at the LTSpice depiction (below) of you feeding an input capacitance through a resistor and measuring the voltage across that C.

You should see about 9 or so mV across the C.

Now make a wire from the top of the parallel connection of L1/C2 to the wire above it.

How many volts now? Oops! Where did the "impedance" go?

Does that make sense to you? Why does it (or not)? Can you explain it?

This is one of the confusing thing you are running into with your measurements.

Version 4 SHEET 1 880 680 WIRE -320 64 -432 64 WIRE 128 64 -240 64 WIRE -432 96 -432 64 WIRE 0 96 -112 96 WIRE -112 128 -112 96 WIRE 0 128 0 96 WIRE 128 144 128 128 WIRE -432 192 -432 176 WIRE -112 224 -112 208 WIRE 0 224 0 192 FLAG -432 192 0 FLAG -112 224 0 FLAG 0 224 0 FLAG 128 144 0 SYMBOL cap 112 64 R0 SYMATTR InstName C1 SYMATTR Value 1.4p SYMBOL cap -16 128 R0 SYMATTR InstName C2 SYMATTR Value 251.9p SYMBOL ind -128 112 R0 SYMATTR InstName L1 SYMATTR Value 100u SYMBOL res -336 48 M90 WINDOW 0 0 56 VBottom 2 WINDOW 3 32 56 VTop 2 SYMATTR InstName R1 SYMATTR Value 10Meg SYMBOL voltage -432 80 R0 WINDOW 123 24 124 Left 2 WINDOW 39 0 0 Left 2 SYMATTR InstName V1 SYMATTR Value "" SYMATTR Value2 AC 8 TEXT -466 248 Left 2 !.ac dec 1e6 999999 1000001

Reply to
John S
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Thanks John S, Ya, I think I have this. The LC is going towards resonance (high impedance) so the voltage drop across the 10meg decrease. I started a new thread before I read this (Critic LTspice model) that is on the same concept. (odd I haven't seen it post yet) At this point I think the stray capacitance adds to the resonating cap and just lowers the res. freq. The stray capacitor losses become important, this is why the writer designed the lowest loss stray capacitance he could.

Mikek

Reply to
amdx

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