Re: VSWR doesn't matter?

Your mistake is that you assume the output of the tx is 50 ohms,

Hi Jimmie,

At the risk of yet another, non-quantitative reply I will repeat:

>a question that has NEVER been answered by those who know what the >>transmitter output Z ISN'T: >> "What Z is it?" >in the case >you stated the transmitter must be matched to the impedance it sees looking >into the transmission line.

THAT is true, and it brings us to the point of all this energy sloshing around until the antenna finally dissipates it out into the Æther. It is the reflection off the mismatch of the tuner (the mismatch seen by the antenna as source to the line going back) that prevents energy from presenting any destructive results to the source

- the whole point of using a tuner in the first place.

73's Richard Clark, KB7QHC
Reply to
Richard Clark
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Correct but I just want to remember that the purpose of the tuner is to match the impedance of the transmitter to the impedance of the antenna/ transmission line.The standing waves can be viewed as a reflect voltage, a reflect current or as a reflected impedance. Besides I thought there had been enough quanitative analysis of the question and was hoping a simple answer may be enough to turn on the light bulb for the OP. If he still wanted to know more I figure he would ask.

Reply to
Jimmie D

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