i am trying to find resistors values R1 and R2 in a voltage divider
> biased transistor circuit.
> the following info is given: Vcc=+24 volts, Rc=680
> ohms(collector),Re=47ohms(emitter).
How many mA current?
.
Re: Voltage -Divider Biased transistor circuit
Mar 19, 2007
8 Replies
That will give you the voltage across the emitter resistor. Add about 0.1 volts to that and that's where the base voltage should be. That's your starting point.
Late at night, by candle light, "Homer J Simpson" penned this immortal opus:
Uh, germanium transistor?
- YD.
Remove HAT if replying by mail.
What part of "starting point" did you fail to understand?
Um, 0.6 would be a better guess.
John
Maybe a Germanium Schottky ;-)
Jfet near Idss?
Somebody recently introduced a sort of floating-gate mosfet where gate threshold voltage can be factory programmed to be above zero (enhancement region) or below (depletion) or very close to zero (which I don't have a name for.)
John
Used to be called "depletion-enhancement". Of course, that was before you could buy depletion enhancers on the Internet.
Cheers,
Phil
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