Paralleling Three Full Wave Rectifier Bridges

If, by that, you mean two inductors in series, how do you square that with; voltage ratio=turns ratio, inductance ratio=turns ratio squared?

That's just plain wrong.

OP is that same eternal-september troll sicko harassing sed with stupid ignorant posts for quite some time now. Don't waste your time on "it."

Assume you have some AC point to point connection to a load.

Then connect a variac at 1:1 settings to the line. What happens ?

The actual power is still flowing to the load.

There might be some reactive (inductive) power flowing through the auto transformer.

Changing the tap settings and more and more power will flow through the magnetic core.

I would disagree with you.

The OP is definitively not a "please do my homework for me" type.

Discussing this topic is definitively appropriate for this newsgroup.

Actually less power, for a constant load, since the voltage reduces.

Derive an expression for the voltages and currents in an autotransformer tapped at, say 30%, hence the flux. Neglect winding resistance.

Sounds like you have it connected backwards! Are you first connected to the AC, then output of the variac to the bridges?

Jamie

Yes. What value would you recommend for this simulation?

As JF stated, it is easy to see the parameters by simply right-clicking on the source. If you want to see them on the schematic permanently, simply click the box in the lower left corner "Make this information visible on the schematic" after right-clicking the source. Easy.

Cheers, John S

Fred, please do not sully this thread. At this point it doesn't matter what the OP had in mind. There is a dialogue going on that is instructional to many and pleasing to others. Please leave us to enjoy ourselves.

Thanks, John S

I knew that already. Shift-alt-ctrl-H will unhide it as well.

I was interested as to why John thought it necessary to hide the parameters, especially in view of the fact that supply impedance has an effect on peak rectifier current.

You omitted what you though might be an appropriate value for the simulation.

Thanks, John S

For John's approximately 100 amp supply, 120 milliohms would be a reasonable guess. 5% regulation is what I'd want on an industrial supply. That gives about 344 amps peak diode current.

Like I told your other fake alias: drop dead.

You go first.

Since you seem disinclined to do that, I'll ask this:

As you rotate the variac, moving the wiper from 100% downwards, does the phase of the output change, or stay in phase with the input?

Try it.

That should tell you something.