Congratulations John! I did not get that far yet!
Congratulations John! I did not get that far yet!
I noted about .01 second. Quite a bit less than 1 second.
At least it is clear that you know how the energy imparts against the spheroid.
I still see it as a fly passing by and farting as it passes.
I would much rather send a swarm of flies, and have them light and fart directionally outward from the surface so that their farts all impart energy against the spheroid.
Hell, send a HUGE mass up, and use rockets to vector that mass into the object with great velocity. It won't matter if it breaks it all up if it also imparted momentum into it to carry the mess out of our path.
We could send a huge 4km diameter net up there, and net the thing and then drag it out of our path.
Yeah... That'll do it... a net.. a big friggin net. Then, the target for us would always be the 'drag chain'. We hit that and apply force to that, and the net and it contents follow.
Hell, we could attach rockets to the drag lines beforehand and when the net captures the rock(s), the rockets fire as they are brought around to face the right way.
Instead of changing its approach vector, we could simply slow it appreciably enough to make it miss us, and also to make it dive into the sun instead of circling it.
Still waiting for that list of consumer goods folks had back in the 70s that had LCD displays in them.
Bwuahahahahahahahahahahaha!
Still waiting for that list of consumer products that had LCDs in them that were out back in the 70s.
Hell, list even a single stereo receiver. They brought display technologies to the fore for years in the consumer channel, so they would be the first to use it.
Name even one.
Can you explain that?
Aim becomes critical under those
Sure. But a trajectory that comes within meters of the desired one wouldn't be hard. And you can detonate a nuke with sub-microsecond timing. You could aim the resulting momentum vector in pretty much any desired direction.
All of this has been done.
John
energy
surface
plasma
targets.=20
=20
the=20
and
x-ray
That is because they are really hard x-ray sources, low energy photons and very small amounts.
Utter nonsense. Most of the gamma from an H-bombs is medium energy, 50 miles of air flash by un-noticed. This is true even for higher energy x-ray.
Not to x-ray photons and even lower energy gamma ray photons. The per meter attenuation factor is orders of magnitude in favor of rock, but just a few more orders of magnitude more air distance more than makes up the difference. Otherwise the hard radiation output of the sun would roast most terrestrial life on the spot.
one of=20
massive=20
more=20
covering=20
aflash
nearby
fireball
Oh great guru, please demonstrate how easy this with all calculations, because i flat admit i can't do them myself. I need power tools (computer based) to even guess half assed and cannot get 1000 meters accuracy. Oh show us great guru.
Gammas are absorbed pretty much by how much mass they pass through.
Silly.
John
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