NPN Common Emitter Bias

If you're building a class AB linear the average collector current can (and should!) vary quite a bit -- for these you use a diode that's in close thermal contact with the transistors to establish the bias voltage to the base. The circuit that I have seen came out of an old Motorola app note (can't remember which one) and uses a 723 for the actual regulation chore.

I _have not_ built one of these for a production system, so I can't comment on how much care and feeding it would demand.

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Tim Wescott
Wescott Design Services
http://www.wescottdesign.com
Reply to
Tim Wescott
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I suspect if the OP had a negative voltage available he would want the output to swing all the way down to it ;-)

Ian

Reply to
Ian Bell

This circuit has two problems, easily fixed.

First, the 100mV drop across R3 and R4 is determined by the base current of Q1, the exact value of which is unknown, and which can change by a factor of say 3 over temperature, etc. So if the drop varies from say 50 to 150mV, then the current-sense voltage will vary from 250 to 150mV, which means we haven't done a very good job of setting Q1's collector current. To solve this we need to stabilize Q2's current. We can do this with a Q1 base-to-ground resistor, R6 = Vbe/I, sized to draw say 3x more current than Q1's base. We can hope this new resistor, R6, will have a higher value than Q1's RF input impedance.

The second issue is loop stability. The loop gain is roughly gm1*Rs, which is 40*0.2=8, times R6/(R3+R4) = 750mV/100mV=7.5, for a DC gain of about 60. Capacitor C1 must provide a dominant pole, reducing the loop gain to below unity before the occurrence of a second pole. The second pole could be due to Rs C2, or due to the input coupling capacitor, C3, with R6. Either way, C1 will probably need to be larger, likely an electrolytic.

Here's the new circuit:

. .---------------------+----------+------- +Vcc . | C1 | | . R1 elec _|_+ Rs . 300mV --- 200mV . | R3 | R4 | . v\\| .--/\\/\\--+--/\\/\\----+--------. . |---, | 50mV 50mV | | . /| | |/v | --- C2 . +-----+----| C| --- 1n . | Q2 |\\ C| L1 | . R2. | C| === . 5mA .-. | GND . etc | | R5 | . | | | not too +------------ out . GND '-' big | . | Q1 |/ . RF IN ---||---+----+------------| . C3 | |\\v . R6 | . | === . GND GND

I question the need for R5, which at any rate must not be too big, or drop more than a few volts. I question it because Q2's collector is a high-Z current-source output, most likely with a low capacitance, much smaller than Q1's base. But, if it's not too large, it won't hurt anything. :-) It could be an RFC.

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 Thanks,
    - Win
Reply to
Winfield Hill

Nice tweaks Win.

My actual circuit, as I recall now some 16 years later (there were a few versions), was as Andrew's, with a 1-2V drop across the sense resistor, minimizing the temperature drift problem. A Miller integrating capacitor across the current-sense transistor ensured stability.

The goal was to overcome the output transistor's native 6:1 beta range (at 25C); confining Q1's idle current to a 2:1 range was considered excellent control...the customary, competing circuit was--get this--a fixed resistor to Vcc! Even more surprising to us non-rf-types, was that 6:1 idle current variation wasn't really all that bad--the actual variation was somewhat less in practice, it worked fine, and only changed the r.f. output by say +/- 30%, i.e. just a dB or so. I wanted to save battery power, which was at a premium, and avoid modulating the transistor reactances and thus interfering with my i/o network optimizations.

Of course the details of desired power output and supply voltage (dictating choice of Q1), input and output loading, and so forth are vital to any particular implementation.

Here's the rationale for R5: In my case Q2 was a 2n3906, which shows about 2pF Ccb _typical_ with a few volts Vce in the Motorola Small Signal Transistor book. That 2pF was about double the _max_ input capacitance of Q1 alone, and added about 90 ohms' reactance in parallel with Q1's base--enough to detune its carefully tuned input.

Isolating Q1(b) from Q2's collector with an inductor was tempting, except that inductors of the d.c.-choke scale were really just capacitors in sheep's clothing at 900MHz, having unspeakable parasitics which loaded the junction and added both resonances, and magnetic-coupling from L1 (bad!!) to the mix.

Although simply strapping Q2(c) to Q1(b) and redesigning the input network might've been okay, it was easier, cheaper (several million of these devices were ultimately built) and sleep-at-night-happier to insert an R5 dropping a volt or two--no more--and thus be sure of being isolated, yet reactance and coupling-free. SMD resistors are surprisingly good at UHF.

Cheers, James Arthur

Reply to
dagmargoodboat

Whoa, interesting, what part was Q1?

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 Thanks,
    - Win
Reply to
Winfield Hill

MRF571. Sweet transistor. You're right though, I mis-read the data sheet. Actual Cin is spec'd at 1.4pF _typical_, which would seem to make the effect of paralleling Q2(c) slightly smaller than I indicated.

That 1.4pF figure, however, was reported at 5mA and f=1MHz. Under bias and near 1GHz the 1.4pF figure no longer holds: the input shifts to being just a tad inductive, best as my foggy recollection interprets these S-parameters.

As I recall it, the non-adjustable input network used caps on the order of 2.2pF, 8.2pF, 6.8pF, etc., so a possible 2pF extra was significant, unwelcome, and adding R5 seemed a cheap way to ignore it and avoid manufacturing variations.

Cheers, James Arthur

Reply to
dagmargoodboat

"Ian Bell" wrote in message news:dpk53e$1j3$ snipped-for-privacy@slavica.ukpost.com...

Ian I am the OP of this post and, after reading all the replies, am certain I am corresponding with people whose knowledge beta is well beyond mine. Appoligies for leaving out critical data in my post. The circuit is indeed RF (7 MHz). I am trying to squeeze 2 watts rms out of a two stage arrangement the first of which is a crystall oscillator and the final an NTE235 NPN in common emitter arrangement. I am trying to maintain linearity in the output waveform and my old BKPrecision oscilloscope indicates I am failing miserably at this. The drive from the oscillator is running about 1 volt peak (i know this is high) which may be part of the problem. The drive is brought in from a 1 turn winding off the oscillator tuned circuit torroid inductor. I had 500 mA of standing DC on the 235 at one point and did indeed achieve the best output waveform at this level of bias. The heat sinked 235 was still running pretty hot at this level so I backed off. I now have a larger heat sink (3 X 6) 1/32 aluminum which will be better I'm sure. Frankly I may have harmonics in the output waveform as well. I'm no expert in deciphering oscope waves unless they are pretty clean. Output load is 50 ohms, which if the equation V0^2 / 2Po is correct would indicate 50 ohms is too high for 2 watts (another problem). Would this be compounding the linearity issue? I got a kick out of your post. You bet, I'm the kinda guy that wants all the peak to peak voltage available from the supply.

Reply to
dgc

Q1 was an MRF571. Sweet part. You're right though, I mis-read the data sheet. C.in is actually about 1.4pF _typical_, which would initially seem to reduce the effect of adding 2pF by connecting Q2(c). That 1.4pF C.in, however, is reported at 1MHz and 5mA, and is not that experienced in actual operation. Under bias and 920MHz it looks to my addled rf-pate like the MRF571's base reactance is less capacitive, shifting to just about neutral or a little inductive, depending.

Without recalling the exact particulars, the input matching network was a fixed network with values on the order of 2.2pF, 8.2pF, 5.6pF, etc., and had to be on-tune, so an extra 2pF was in any case unwelcome.

And that, my friends, is the tale of the resistor R5, and how she came to be.

Cheers, James Arthur (posted this earlier in the day, but it failed to show)

Reply to
dagmargoodboat

It is normal to use a low-pass filter network at the output of a transmitter to remove the inevitable harmonics; although you can certainly minimise harmonics by making the circuit as linear as possible; however, simple

2-stage oscillator-PA transmitters of the type you describe are typically operated with the PA stage in class C i.e. no standing bias. You don't need a linear PA unless you're amplitude modulating the drive.

As for the RL = V^2/Po issue, where RL is the load resistance "seen" by the collector, you need an impedance transforming (matching) network at the output which makes the 50 load "look" like the desired RL value to suck-out the required amount of power. The transistor then needs sufficient drive to make the requisite amount of AC collector current available.

It is normal to make the peak voltage swing at the collector close to the power supply Vcc to maximise efficiency, but it sounds like you might be willing to live with less than ideal efficiency. You could get 2W out with less than a 12V swing.

One final point: it helps if you have a way to smoothly adjust the drive level from the oscillator - perhaps by running it off a seperate variable power supply. If the output level changes by sudden jumps, and does not vary smoothly as you adjust the drive level, you have spurious oscillation problems.

Reply to
Andrew Holme

I am not really an RF chap, although I did do some in my youth with tubes, so don't take what comes next as coming from an RF expert. If I wanted 2 watts out of the final stage then I would certainly be considering operating it in class C, in which case DC biassing does not come into it. The classic class C circuit has an resonant circuit in the collector to remove a lot of the harmonics although some will still remain. These are usually removed by a subsequent LC filter circuit. As for 2 watts into 50 ohms, this implies an RMS output voltage of 10V so you would need a 30V supply - do you have this? If not the classic way to overcome this is with an RF transformer arrangement.

HTH

Ian

Reply to
Ian Bell

Andrew Holme wrote: [snip]

I missed a factor of 2 in the above equation. It should be: RL = Vcc^2 / (2*Po)

Although Po = Vcc^2 / (2*RL) is the maximum power available for a given supply voltage and collector load, I also find it helpful to think about Po = 1/2 * Icpk^2 * RL since the transistor is a current-output device.

Reply to
Andrew Holme

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