my hypothesis/proof that pi is a normal number

Nov 01, 2015 11 Replies

Hi,



I think there is proof pi is a normal number based on tests I did with it.



I hypothesise (based on testing to 60million digits of pi) that the vast majority of any block of 80,000 digits selected from within pi will not be normal, ie there will be an unequal distribution of digits



0 to 9 within each of the 80,000 digit blocks. However since larger block sizes, ie 10million digits, are shown to approach equal digit distribution, this means that the digit 0 to 9 distribution in each of the 80,000 digit blocks must be random, otherwise when the 80,000 digit blocks are added together they would not create a larger sequence that approaches a normal number, unless there was a very apparent order (lack of randomness to the digits in a comparison of the 80,000 digit blocks) which is not apparent.

summary: If the lack of normalcy in the 80,000 digit blocks is random then the full sequence of pi is a normal number, and if the lack of normalcy in the 80,000 digit blocks is not random, then there would be an easily seen pattern in pi that is already shown to not exist.



cheers, Jamie


Y'er a bit late. It certainly appears that pi is a normal number, not only in base 2 and in base 10 but in other bases as well. But sadly, as noted above, there is no proof. (Some very recent empirical analysis of the first 16 trillion binary digits, corresponding to a bit less than 5 trillion decimal digits -- by us and several co-authors -- strongly suggests that pi is normal base 2, but again this is not a proof.) So, all you have to do is compute Pi to a zillion digits in a zillion bases, run the digit distribution, and you'll get your Ig Nobel Prize for wasting everyones time and for posting an off topic message without clearly labeling it as OT.

Jeff Liebermann jeffl@cruzio.com 150 Felker St #D http://www.LearnByDestroying.com Santa Cruz CA 95060 http://802.11junk.com Skype: JeffLiebermann AE6KS 831-336-2558

I am not a mathematician by any means, so please advise how PI may be calculated to such a large number of digits. My guess is that it is approximated by determining the circumference of a circle as a number of isosceles triangles with legs = radius and adding the lengths of the bases will approach PI as the number => infinity.

But on a practical basis, there is a limit to the precision of any such physical measurement, perhaps based on the Planck Constant

formatting link
and the Heisenberg Uncertainty Principle
formatting link
So, there is an inherent uncertainty in the position of the points of reference for such a calculation, at least on atomic or molecular scales. On macroscopic or astronomical scales, the position has an uncertainty based on relativity, and the accuracy to which any such physical measurement might be made.

Paul

Usually using some variation of the Machin formula:

formatting link

This gives you more than one new decimal digit per iteration, because the slowest converging term is the odd powers of 1/5.

There is no such limit to the calculation of the theoretical ratio c/d. No physical measurement is required.

Clifford Heath.

Well, Pi is just "1" in base Pi. Numerical bases are nothing more than an interface to physical storage - stones, check marks, fingers, bits, trellis codes, flash cell levels, etc. That's why Pi remains in symbolic form as formulas are processed.

I will not see posts from astraweb, theremailer, dizum, or google because they host Usenet flooders.

Hi,

Pi can be expressed as various continued fractions or infinite series:

formatting link

There are obvious fractal patterns just in the infinite series themselves that are what pi is. Although the digits of pi look random there is some underlying order related to these infinite series and/or continued fractions too I guess.

cheers, Jamie

So I wonder why anyone would want to calculate PI to such extreme precision. I just tried my method of calculating:

PI = n * sin(180/n)

n f(n)

24 3.1326 96 3.14103 3600 3.1415922548465383558965214766656 36000 3.1415926496023605393251041371138 PI 3.1415926535897932384626433832795

Using PI = n * tan(180/n)

n f(n)

24 3.1596599420975004833166349778332 96 3.1427145996453682981688590937721 3600 3.141593451076576297997908326304 36000 3.1415926615646586640671548189975 PI 3.1415926535897932384626433832795

As expected, the values converge from below and above using sin() or tan()

The average of the values using 36000 is:

3.1415926555835096016961294780556

This differs from PI by:

1.9937163632334860947761063839209e-9

Paul

Sounds like there is a false presumption somewhere...

David Bailey! Years ago i used some of his multi-million digit math algorithms to write my own My Dear Aunt Sally in Fortran. Allocate/deallocate large blocks of memory as needed without losing a single byte (AKA "memory leak"). He analyzed how to program groups of multiplies to avoid "burps" caused by cache refilling at inappropriate times. He is the computer programing master on how-system-works and work-arounds.

On Sun, 01 Nov 2015 14:32:25 -0800, Jeff Liebermann Gave us:

That would be the "Usenet Ignoble Prize", no?

The only hypothesis these "digit hunters" are proving is that observation of huge amounts of data is not a substitute for theoretical insight.

Hi,

Ya I think so, but I have found a difference in how pi compresses versus all the other sequences I've tested, up to 60million digits, so I'm just tracking down what that difference is exactly now.

The compression difference I am getting is most likely due to one or more of these things or a combination of them (I can find out for sure after some more checking)

  1. the digits of pi have fewer "local" (ie within 1million consecutive digits occuring anywhere up to 60million digits) matched repeating pairs of digits ie 3,4 or 5,6 repeated at least twice.

  1. the digits of pi have fewer "local" (ie within 1million consecutive digits occuring anywhere up to 60million digits) matched repeating pairs of digits with equal spacing occuring at least three times ie.

3,4 spaced in the sequence:

3,4,x,y,z,3,4,a,b,c,3,4 (matched spacing gap of 3 digits between 3,4)

Or could be something else or related to the above at least for the difference I think I found in pi.

cheers, Jamie

Join the Discussion

Have something to add? Share your thoughts — no account required.

Didn't find your answer?

Ask the community — no account required