I have a circuit that generates a floating ( both sides) ~ +/- 1500V. The final output is generated by a standard diode cap multiplier block, giving 1mA current. The +ve output is monitored via a 1G resistor into an opamp then an ADC. The negative output is allowed to follow the positive which is in a closed loop controlto set the output voltage. What is the best way to monitor the -ve output ? 100:1 probe ? a fet probe? 1000:1 probe ? Output is pulsed in the small uS range... TIA
Measuring high voltages
What do you mean by 'floating'? Does the measuring device also float, or is it referred to some other potential/ground? How accurate do you need this to be?
Also - are you expecting to follow the dynamics of this pulsed voltage? To what bandwidth?
How is it pulsed if it is derived from a CW multiplier?
Tim
-- Seven Transistor Labs Electrical Engineering Consultation Website:
Here's a reasonable priced 20ua meter, series seven 10meg and one 5 meg resistors in series with the meter. and it will read full scale at 1500V. Maybe I'd use ten 10meg in series and the you could see an over voltage condition. Caution High Voltage, us proper techniques and insulation. Also remember it's a negative voltage when hooking it up.
20ua will have negligible affect on your voltage. Mikek
Forgot the meter,
The -ve of the + supply is connected to the pos of the -ve supply, which is ground referenced. 2-3% would be good...
No just the peak DC voltage which is about 50uS
there's a front end pulsed oscillator feding the D/C multiplier.
I'd try one of those TV flyback HV probes. They are about 10G ohms and will lightly load the supplies. But they are not frequency compensated, you might have to build one yourself if frequency response is important.
Cheers
On a sunny day (Mon, 30 Mar 2015 23:17:37 +0100) it happened TTman wrote in :
If it is truely a 50 us pulse from 0 to whatever, then you could use a capacitive divider, and measure AC.
Else as you use a resistor divider for +, why not do the same for -. BTW if you connect both together the output should be zero for DC. If you have problems with negative voltages, then hang a resistor from the end of the - divider to some stabilized +, so reference + of the ADC range
Nope, like 1.1 G.
Join the Discussion
Have something to add? Share your thoughts — no account required.
Didn't find your answer?
Ask the community — no account required