ok, say you've got a DC voltage supply in series with a switch and an inductor, the inductor ties back into the power supply completing a circuit. ok, the switch is closed for a little bit then opened.... from what I understand this causes the inductor to produce a hell of a voltage across itself cause it doesn't like the drastic change in current. now the switch is open, the circuit it broken there's no loop for the current... my question is... is there current flowing? even though it's a broken line because of the switch? If the inductor is pushin current out of itself, is there current flowing through the inductor or just out one end of the inductor? I've heard you can really mess up a switch this way, with that high voltage across the inductor hanging on one end of the switch... but if the other end of the switch is floating, how does the switch get damage? I mean, there can't be any current flowing through the switch, can there? If one end is floating?