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It depends on the cos(phi) factor of the load. UPS are mostly sold to be used with computer equipment. IIRC computers have a typical cos(phi) around 0.72 So that would be 2200 * 0.72=1584W.
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Reply to nico@nctdevpuntnl (punt=.)
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** AC supply loads that use rectifiers and filter capacitors to produce a DC supply normally have a poor power factor or PF . Without any correction device or circuits, the PF can easily be a low as 0.4.
The current draw consists of brief (1 to 2 mS) pulses that coincide with the AC supply voltage maxima.
Since no phase angle exists between current and voltage - no " phi " can be assigned.
The BASIC definition of PF does not rely on phase angle:
PF = watts / VA
where
V = AC RMS volts & A = AC RMS amps
When the AC current draw is a stream of brief pulses, its RMS value is much higher than the same average current draw in the form of a sine wave.
I could definitely say this is one of my weak points in Sys/Net Admin.
-- I hear you guys talk and is like chineese. I feel like one of those little old ladies that is trying to understand when somebody tells them how to email and burn CD's. LOL
Well I think somebody posted around 1800 Watts more less.
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