diffamp with Vcc = 0

John Larkin · 2013-05-24T15:41:04+00:00

This is sort of cute. The amps have their collector resistors returned to ground, so they are running with collector voltages below their base voltages. The transistors are almost saturated (they are, by some definitions) but the voltage gains are still roughly as predicted by the old EROT, gain = collector resistor drop times 40. If the transistor models are good. Version 4 SHEET 1 1348 680 WIRE 1056 -432 944 -432 WIRE 1152 -432 1056 -432 WIRE 1056 -400 1056 -432 WIRE 944 -304 944 -432 WIRE 1152 -304 1152 -432 WIRE 272 -272 160 -272 WIRE 368 -272 272 -272 WIRE 272 -240 272 -272 WIRE 944 -192 944 -224 WIRE 1280 -192 944 -192 WIRE 1344 -192 1280 -192 WIRE 160 -144 160 -272 WIRE 368 -144 368 -272 WIRE 1152 -128 1152 -224 WIRE 1280 -128 1152 -128 WIRE 1344 -128 1280 -128 WIRE 944 -80 944 -192 WIRE 1152 -80 1152 -128 WIRE 160 -32 160 -64 WIRE 464 -32 160 -32 WIRE 880 -32 464 -32 WIRE 1296 -32 1216 -32 WIRE 368 32 368 -64 WIRE 464 32 368 32 WIRE 736 32 464 32 WIRE 944 48 944 16 WIRE 992 48 944 48 WIRE 1040 48 992 48 WIRE 1152 48 1152 16 WIRE 1152 48 1040 48 WIRE 160 80 160 -32 WIRE 368 80 368 32 WIRE 736 112 736 32 WIRE 1296 112 1296 -32 WIRE 1296 112 736 112 WIRE 0 128 -80 128 WIRE 96 128 0 128 WIRE 512 128 432 128 WIRE -80 192 -80 128 WIRE 160 208 160 176 WIRE 224 208 160 208 WIRE 256 208 224 208 WIRE 368 208 368 176 WIRE 368 208 256 208 WIRE 512 208 512 128 WIRE 256 240 256 208 WIRE 1040 240 1040 48 WIRE -80 320 -80 272 WIRE 256 368 256 320 WIRE 1040 368 1040 320 WIRE 1040 368 256 368 WIRE 256 400 256 368 WIRE 256 528 256 480 FLAG -80 320 0 FLAG 272 -240 0 FLAG 256 528 0 FLAG 512 208 0 FLAG 0 128 IN FLAG 464 -32 X FLAG 464 32 Y FLAG 1056 -400 0 FLAG 224 208 E1 FLAG 1280 -192 A FLAG 1280 -128 B FLAG 992 48 E2 FLAG 0 0 E2 SYMBOL npn 96 80 R0 WINDOW 0 87 20 Left 2 WINDOW 3 64 55 Left 2 SYMATTR InstName Q1 SYMATTR Value 2N4401 SYMBOL npn 432 80 M0 WINDOW 0 96 20 Left 2 WINDOW 3 73 55 Left 2 SYMATTR InstName Q2 SYMATTR Value 2N4401 SYMBOL res 240 224 R0 WINDOW 0 64 42...

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Fred Abse 13 years ago

Or production.

Good so far.

Should correctly be

Then you spoil it. The watt hour is a quantity of work, equal to 3600 joules.

Watts = work/time, hence watt/hour would be energy per time squared - joules per (second squared *3600). Not a lot of use for that.

Correct, quantity of work. Named after the 18th century English brewer who first measured the mechanical equivalent of heat. His brewery cellar was the ideal, probably the only, place at the time with a sufficiently uniform temperature over time to enable the experiment. His results were surprisingly accurate.

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"For a successful technology, reality must take precedence over public relations, for nature cannot be fooled." (Richard Feynman)

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hamilton 13 years ago

OK, 948 posts on electronics.....

over 10,000 posts on how bad everyone else is.

So about 10% about electronics and over 90% other.

Statistics tell the true story.

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Jim Thompson 13 years ago

[snip]

Done. ...Jim Thompson

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| 1962 | I love to cook with wine. Sometimes I even put it in the food.

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Phil Hobbs 13 years ago

*gasp*

It's all over, folks.

Civilization has no officially come to an end.

But what about the children? ;)

Cheers

Phil Hobbs

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P

Phil Hobbs 13 years ago

*gasp*

It's all over, folks.

Civilization has no officially come to an end.

But what about the children? ;)

Cheers

Phil Hobbs

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Jim Thompson 13 years ago

The Pecksniffian echo is now stuttering... posting the same tripe twice ?:-) ...Jim Thompson

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Jamie 13 years ago

knows

I see smoke!

Jamie

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Jamie 13 years ago

Lets see if I can remember this correctly...

1 J = the work with 1 Newton over 1 meter, or something like that. it's been a while.

Jamie

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John Larkin 13 years ago

people

AlwaysWrong!

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John Larkin 13 years ago

Oh! Oh! What have I done? Generations of future Engineers will miss being saved by Jim's web site, will be lost to Fine Arts.

Boy, that Thompson guy sure knows how to get even.

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Jim Thompson 13 years ago

A good start would be you learning to read >:-} ...Jim Thompson

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Fred Abse 13 years ago

Correct.

Joule probably worked in feet, pounds, and Fahrenheit, back then. Tanks of water, paddles, and falling weights. Very small temperature rise.

Rumford started it off, boiling water, boring gun barrels.

"For a successful technology, reality must take precedence over public relations, for nature cannot be fooled." (Richard Feynman)

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Jamie 13 years ago

And remember this..

1000g of figs = 1 FigNewton!

Ok, that's a bad one..

Jamie

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Spehro Pefhany 13 years ago

More like the force from ~100g* under normal gravity.

~101.9716

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diffamp with Vcc = 0

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