Capacitor Impedance is less than ESR?

If the two graphs are not swapped, I'm having a hard time with this

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Last page, graph in the upper right compared to the graph immediately below that.

My question is: How can the capacitor's impedance be lower than the capacitor's ESR?

Thanks.

John

"John KD5YI"

** It ain't and the graphs do not say it is.

You have failed to realise the scales on the LHS are **ratios** - not actual values.

What the graphs show is that:

ESR is fairly constant above 2 kHz and depends mostly on temperature - ranging over 100:1 from -55C to +105C.

Impedance falls with rising frequency, but is limited by the series ESR value at any temperature.

..... Phil

"John KD5YI" schrieb im Newsbeitrag news:RJgnk.505$mP.222@trnddc03...

Hello John,

You may have overlooked the meaning of the plot.

Upper plot: Ratio relative to ESR @120Hz, 25° Lower plot: Ratio relative to impedance @120Hz, 25°

Impedance Z = 1/(jwC) + ESR

The ESR is only the resistive part(value) of the impedance.

At 120Hz, the value of 1/(w*C) is much larger than the ESR. That's why the ratio in this impedance plot has suich low values at higher frequencies.

Best regards, Helmut

You are absolutely right. Indeed I failed to read "ratio" and took it for absolute.

Thank you, Phil.

John

You are correct, too, Helmut. I failed to read "ratio" on the graph.

Thanks.

John