If the two graphs are not swapped, I'm having a hard time with this
Last page, graph in the upper right compared to the graph immediately below that.
My question is: How can the capacitor's impedance be lower than the capacitor's ESR?
Thanks.
John
If the two graphs are not swapped, I'm having a hard time with this
Last page, graph in the upper right compared to the graph immediately below that.
My question is: How can the capacitor's impedance be lower than the capacitor's ESR?
Thanks.
John
"John KD5YI"
** It ain't and the graphs do not say it is.You have failed to realise the scales on the LHS are **ratios** - not actual values.
What the graphs show is that:
..... Phil
"John KD5YI" schrieb im Newsbeitrag news:RJgnk.505$mP.222@trnddc03...
Hello John,
You may have overlooked the meaning of the plot.
Upper plot: Ratio relative to ESR @120Hz, 25° Lower plot: Ratio relative to impedance @120Hz, 25°
Impedance Z = 1/(jwC) + ESR
The ESR is only the resistive part(value) of the impedance.
At 120Hz, the value of 1/(w*C) is much larger than the ESR. That's why the ratio in this impedance plot has suich low values at higher frequencies.
Best regards, Helmut
You are absolutely right. Indeed I failed to read "ratio" and took it for absolute.
Thank you, Phil.
John
You are correct, too, Helmut. I failed to read "ratio" on the graph.
Thanks.
John
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