capacitance of this inductor

Can't you figure it out for yourself? its a simple resonant circuit. Subtract the minimum inductance for a given coil from the maximum, and divide it in half to allow for some tuning range, then use that value and the desired frequency to calculate the required capacitance.

There are eight different coils and 100 US FM channels You don't really expect someone to give you all 800 answers, do you?

Those are fine, as far as they go, but it's not far, only to 0.465uH. That's a rather limited HF operating region.

Taking the 0.465uH inductor, they don't give the SRF, which many inductor manufaturers provide, but they do test at 50MHz. So if we assume an SRF above 100MHz, that limits the coil's self-capacitance to 5.4pF.

In message , dated Fri, 15 Sep 2006, Michael A. Terrell writes

I think he wants the self-capacitance. Only the manufacture or a user would know that, and it SHOULD be on the data sheet.

But if the coils are good to 500 MHz, the self-resonance must be higher than that, so, taking the maximum inductance, find the capacitor that resonates at 500 MHz. The self-capacitance must be less than that.

Thank you John, you indeed understand the question, and thank you Winfield, since you gave me the quick estimate I was interested in and how to find it. I too agree it should be on the data sheet.

Gary Peek

Bit late maybe but for a bare wire single layer solenoid ...

Coil capacitance = radius in centimetres.

If wire is insulated or moulded in plastic then double the value. john