I know how to bias FETS, but how this particular Class A linear bias scheme works has me completely stumped, since the DC is totally blocked from the FET's gate by capacitors. Anyone have an explanation of the bias of this particular FET circuit? The small signal amplifier circuit can be seen at Watkin's Johnson Web site at:
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. Any help in understanding this particular bias circuit would be most appreciated!
In every schematic on that data sheet, it seems that there is a DC path to ground (either a resistor, an inductor, or a series combination). That means that the bias voltage is zero in all these cases.
Thanks John, but since the bias voltage is, as you say, zero volts at the gate, then how can it function as a Class A small signal linear amplifier? I would think it could only function as a Class C amp...?
Thanks Again,
Bill
John P> > I know how to bias FETS, but how this particular Class A linear
Thanks for the feedback Phil. I understand what you are saying, but since WJ "recommends" that this part never go positive at the gate, how can an input signal have the appropriate voltage swing (head room) it needs for linear operation (since it is biased at zero volts, but can only swing negative)?
This particular fet passes about 140 mA when its gate to source voltage is zero and its drain to source voltage is 5 volts. Once biased that way, the drain current increases when the gate voltage goes incrementally positive, and decreases when the gate voltage goes incrementally negative. This is very ordinary biasing for a jfet.
If the gate to source voltage goes negative to somewhere between -1.5 and -3, the drain current cuts off (falls below .6 mA). At some rather small positive gate to source voltage, the gate diode becomes forward biased and is no longer insulated from conducting current into the channel. Normal signal swing positive peaks stay below this voltage.
That's not an accurate statement as it stands. If you said, it's not an enhancement-mode mosfet, that'd be correct. A depletion-mode mosfet works exactly the same as Bill's FH101 GaAs MesFet: full conduction at zero volts, and requiring a negative gate voltage to turn off, yet it's still a mosfet. An example of a depletion-mode mosfet is my favorite Supertex LND150,
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which has myriad uses, some of which I've detailed on s.e.d.
My summer students just made a cool two-terminal, self-powered current regulator using an LND150. This floating current-source / current-sink operates from 1 - 250mA, with a compliance range of 6 - 500V. It has a current-pulse feature, that's especially useful for high-voltage power-supply testing, such as for piezo amplifiers; tube-amplifier aficionados, take note. Yep, just one more example of why I recommend the LND150 (TO-92 package) and its SMD mate, the LND250. Supertex' DN2540N5, in a TO-220 power package, is a useful 400V 150mA depletion-mode mosfet.
Most MOSFETs *are* N-channel fets. The rest are P-channel fets. And most MOSFETS have Idss=0.
It's actually a mesfet, a metal-gate GaAs fet. It draws a considerable drain current Idss at Vg=0. Negative gate voltage reduces Id until pinchoff, at about -1.5 on the gate. Positive gate voltage will enhance it, up to the point that the gate starts to conduct, with enhanced Id of about 1.5 Idss typical. PHEMTS enhance better, roughly
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So what?
It sounds like you\'re trying to make yourself look like an expert
who can relate vacuum tube grid leak bias to MOSFET gate current.
It won\'t work, and you don\'t even know why.
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