average value of current pulses?

Yes, but the time constant doesn't need to be so long. With those values, it's going to take almost one minute to fully charge the capacitor. I would try 10k and 100uF.

This will work but it may give difficulty. The peak voltage is only 50mV across the .1 ohm resistor and the average voltage will be less than 10mV. That's a small number prone to errors with an electrolytic capacitor. I would use a film capacitor of several microfarads with hundreds of "k" in the resistor to get a time constant about one second. It is now 10 seconds, longer than necessary. You may want a little more sense voltage to work with by making the .1 ohm resistor .2 or even .5 ohms.

What are you going to do with the average value for current? If it is going to feed any type of processor or controller for indication or control, you might consider doing A to D conversion and numerical averaging in the digital domain in that processor. It could be a single chip solution without any analog integration, large caps or other parts.

What exactly are these " randomly spaced intervals " ??

Every other Tuesday afternoon if it rains ??

...... Phil

Random intervals can't be described exactly. That's because, I think the theory goes, they're random.

John

So, each pulse has a charge of 13x0.5 mC = 6.5 mC. There are about 15 of these pulses per second, so:

The average current is about 100 mA.

Mark