3.3V Regulator

This is such an open-ended question I don't know where to start. I think you need to give more information. Like, input voltage, and if heat/efficiency matters.

Hmm, a basic Zener of aprox 3.8v volts on a basic base driver circuit maybe ? i guess it would be in impact mode at that low level instead of zener mode. oh well

Well, I think that input voltage is between 9 adn 12 VDC, the current output must be at leas 1.5 Amps

Which means that the package size is likely to be be determined by thermal dissipation if a linear regulator is used ( Pd = Vin - Vout X Iload so up to 18W ! ) so a switcher seems the best idea.

Graham

First you said 2 amps. 1.5 amps is significantly different - use an LM317. They come in SOT-223, but you'll need a significant heat sink.

Good Luck! Rich

do you know the sharp series?, like the 070XH02, how I can use this?

Use a National LM2678 or similar. These switchers are actually good for 5A. I've been using them and they work well. I believe there's another part number that works up to 2 or 3 A. The LM2678 is adjustable, but there is a 3.3V-only version.

With 9-12V in, you "have" to use a switcher. A linear is going to generate tons of heat.

You'll never get that much heat out of an SOT-223 package.

Graham

No.

A Google for "070XH02" suggests it's obsolete.

Graham