--- I don't think that's true. (View in Courier)
Consider a conventional full wave bridge:
+----+---------+ | | | MAINS>----+ | [CR1] [CR3] | | |A |K P||S +--[C1+]--+--->V+ R||E | | I||C +---------|--->V- | | |A |K MAINS>----+ | [CR2] [CR4] | | | +----+---------+Note that (neglecting the secondary I²R losses) for a 50VRMS secondary winding the voltage from V+ to V- will be:
VDC = (VRMS * sqrt(2)) - (2Vf) = (50 * 1.414) - 1.5V ~ 69.2V
Since either V+ or V- could be used as a [ground] reference, then the output of the supply could be either +62.5V or -62.5V, but not + and - at the same time. An artificial reference could be constructed so that the output of the supply would be symmetrical and "simultaneously bipolar", but in that case the output would be
+/- 34.6VDC, not +/- 50VDC.In order to get simultaneous + and - outputs what's usually done (if separate transformers aren't used), is this: +--[CR2>]--+--->V+ | | +--[CR1>]--+ | |+ MAINS>----+ | [C1] P||S | R||E----------+--->GND I||C |+ | | [C2] MAINS>----+ | | +--[