"Ian Macmillan"
"Phil Allison"** That is the scenario posed in text book examples of the question.
>>
>>
>> Be instructive to connect a scope across the uncharged cap and observe
>> what really happens when the charged one is first connected. Try a
>> couple of
>> 1uF film caps.
>
>>
> What really happens depends on the resistance of the path between the
> charged and uncharged capacitors. Initially when connected the uncharged
> capacitor is at 0 volts, so the current that initially flows is E/R,
> asymtoting to zero when the capacitor voltages match. With your 1uF film
> caps, there could be an oscillation, particularly if you just shorted them
> together.
Often the poor student is also asked to assume the capacitors are ideal.
This really throws 'em.
If you just short the** In practical caps, the high frequency ESR and Q values are crucial to the outcome.
> capacitors together, the resistance is in the connection or internal in
> the
> caps - its low and the current is high but it works out the same.
Plus the series inductance of the parallel assembly.
I am** Please don't lose any sleep over it .
> unhappy with my piece which was badly done, and I'll re-do it in due
> course.
Be assured, others have.....
As to the point of it, obviously none for you, but could be relevant for** Did I use a " * " where I should have used a " ^ " ?
> others.
> By the way, your response also has a math error.
Where is the usenet etiquette on this convention published ?
I normally avoid any chance of mis-interpretations takes and just write the word "squared".
.... Phil