I am trying to regulate my dc voltage of 5.8-6.5Vdc supply to a 5vdc I want to use the LM7805 regulator, not sure the minimun inpu voltage spec.. Do anyone know th minumun input voltage needed to ensur the LM7805 function well? And what will be the ideal output capacito to be used
That depends. A standard 7805 will work above 7v (unfortunately) and there's high efficiency version that could work as low as 6.
Instead of that 7805 regulator, look for DC-DC converter, they can handle voltage more efficiently than the regulator.
If you can't find that, you could try this quick and dirty emitter-follower transistor design. Input of minimum of 5.7v to collector, a resistor from collector to base (to turn it on), a 5.7v Zener diode in reverse bias from base to ground, and the output should be a 5v. Not efficient but cheap.
That also varies depending on the load and the ripples.
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That design takes about a four volt drop across the NPN pass transistor. You can lower the drop if your bias voltage (the resistor to the collector) isn't connected to the collector, but connected to a source that is ~4 volts higher than your output.
That technique is used in linear supplies to make them more efficient since the bias supply is just saturating the transistor - not supplying the output current.
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Some standard 780x regulators require 3V headroom. Low drop out types can work at lower supply voltages..
Here is one example but I'm not saying it's the best for your application...
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The summary says this one works down to 5V + 0.47 = 5.47V so you should be ok at 5.8V min. but you don't say how much current you need?
Sometimes LDO types can be unstable (prone to oscillate). You normally have to use capacitors with the correct ESR (refer to the data sheet/Apps note) to ensure stability.
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