high current pulse?

Wire sufficient FGCs in parallel to give you 1 Farad.

Charge to 1kV

Discharge through 10 turn 6" diameter coil made from 1/4" copper rod.

Important .... just before you discharge, phone for the ambulance because the ignorance that you display is certain to kill you during the process.

(Wasn't his advice given here recently?)

--- Well, let's see...

#6 AWG wire has a diameter of about 0.167" and a resistance of about

The steel rod has a circumference of:

C = pi D = 3.14* 1" = 3.14 inches,

so the length of the first layer will be

L1 = C n = 3.14" * 71 turns = 222.94" ~ 223"

Since the wire has a diameter of 0.167", the second layer will be wound on the diameter of the rod plus twice the diameter of the wire:

D2 = 1" + 0.167" + 0.167" = 1.334"

and its length will be:

L2 = pi D2 n = 3.14 * 1.334" = 297.4" ~ 297"

So, the total length of the winding is:

L = L1 + L2 = 223" + 297" = 520"

Since the wire has a resistance of 0.395 ohms per 1000 feet, that's

Assuming your battery's internal resistance is about equal to the winding's resistance means that you'll have 12V across 0.034 ohms,

and the current into the coil will be:

E 12V I = --- = -------- ~ 353 amperes R 0.034R

Since you're only getting 5A into the coil I'd suggest that your battery isn't fully charged, that it's bad, or that whatever's between the battery and the coil is limiting the current.

BTW, if you do get 353A into the coil, it'll be dissipating:

P = IE = 353A * 6V = 2118 watts

which is about 50 watts per foot, so it'll get very hot very quickly.

The battery will also be dissipating the same amount of power, so you'll need to be very, very careful when you're experimenting with it and if you ever get it working right.

JF