How much can I disclose?
____________________ | _____ |_____
120 vac ) || ( 8 vac | |
60 HZ ) || ( R 1 R
2
6 A ) || ( 14 Ohms 21 Ohms
50 Turns ) || ( 7 Turns |__________ | |___________________|
From this schematic ( I hope it is readable ), I can determine R total as:
1 / 14 + 1 / 21 = 1 / .119 = 8.4 Ohms. The current in this circuit is:
I = 8 / 8.4 = 952 mA (800 mA actual reading).
Question: From this data, can I determine the available current in the secondary?
952 mA is the apparent current but, the actual available secondary current is much, much, higher.