Low cost mains power supply

In most DIY stores you can find these cheap Chinese digital timers to turn you lamps or appliances on at specified time. The thing I'm wondering is, how do they power the digital circuitry from

110VAC in a device costing only $5-$10? Are they using a transformer or are they directly powering the digital circuitry from the AC voltage?
Reply to
Nomen Nescio
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For a small amount of power (and efficiency in the single digit percentage range), a rectifying bridge, a zener for regulation, a current limiting resistor and a capacitor or two is all you need. A switch and fuse are probably a good idea too.

Isolation is key for safety on something like that.

Reply to
Robert Wessel

I've got one here it has a capacitive dropper and a tiny 4mAh NiCd cell (I assume NiCd because the charge rate printed on it is C/10) the AC switch is a 48V relay and there's a TO92 device which probably switches it. image in ABSE

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Reply to
Jasen Betts

o
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I one time needed a super efficient 5Vdc [allowed to be directly connected to the mains] power supply but had NO room for the size of caps needed for the normal drop stage. So, I designed up a small circuit that connectd the mains to the rectifier diode starting at zero crossover and DISCONNECTING when the mains input went above around 7V and started to take the 5 Vdc output voltage up to 5.1, or so. thus I had efficiency AND regulation.

Reply to
Robert Macy

Look at some of the smart meter app notes from Atmel, Microchip, etc. They have examples of small offline supplies.

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Chisolm 
Republic of Texas
Reply to
Joe Chisolm

The mains voltage rises to about 7V input (5V output) in about 100us and to about 7.1V input (5.1V output)in 111us. So you have about 11us to charge your storage capacitor. Then, the storage cap must hold up the 5v for about 16ms until the next rise (this assumes 170V peak, 60Hz, half-wave).

I must be missing something very important and I would appreciate your help in understanding what it might be.

Many thanks, John

Reply to
John S

John S schrieb:

I consider it useful to mention mains voltage (and frequency) when presenting such calculations.

I also think that "7.1V" is somewhat tight.

The Harris HV-2405E used this principle, of course with wider thresholds.

Oliver

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Oliver Betz, Munich http://oliverbetz.de/
Reply to
Oliver Betz

They were mentioned (170V peak, 60Hz, half-wave) in the part that you snipped.

And of course, it all depends on the current consumption. With very low currents used, the cap would only discharge slowly.

Reply to
Arlet Ottens

correct, sorry!

Oliver

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Oliver Betz, Munich http://oliverbetz.de/
Reply to
Oliver Betz

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