I have an RL parallel circuit. The AC voltage is 120 and the frequency is 60 Hz. One branch has a resistor (60 ohms) and the other branch(the one parallel to the resistor) has an inductor with 60 mH.
The inductive reactance of my inductor is
22.61(rounded to nearest hundreth) ohms.My question is this, to find the impedance I use Z = 1/(sqrt([1/60]^2 + 1/[22.61]^2)) ?
-- conrad