See the way I look at it is, if you use summation convergence of its simple root along two processing line, then isn't the signal sampling needed reduce by the square factor thereof?, and since there are four edges, you can reduce the sampling by a further 4 times. or have the same sampling time, and achieve an extremely high signal definition.
and since any transition time in the clocking signal =3D 0 ; the result of instantiating two processing lines into 1 coherent perfect (limit "iff" (sync_difference >transition_max) is true) instantaneous transition square wave.
do you see what I mean Bret?