Im my thread "transistors" from 22/9/04 Roger explained me how to determine the C and E with the hfe test after determining the B. I did a test with a H9012, which is a pnp(diode test).(Black at B measuring
600 mv versus E en C) B,E and C are marked on the transistor. There's no doubt about this. The two hfe values are 174 and 41. So i took the 174-combination. It's quit the opposite.Am i doiing something wrong.