hfe

Im my thread "transistors" from 22/9/04 Roger explained me how to determine the C and E with the hfe test after determining the B. I did a test with a H9012, which is a pnp(diode test).(Black at B measuring

600 mv versus E en C) B,E and C are marked on the transistor. There's no doubt about this. The two hfe values are 174 and 41. So i took the 174-combination. It's quit the opposite.

Am i doiing something wrong.

Reply to
j van c
Loading thread data ...

Well, that's a strange result.

Many transistors work equally well even if you reverse the C and E connections, but it should work better if you connect it as the manufacturer has intended it to be used.

You could try to use it in a common type of circuit, like a common emitter amplifier circuit, and try it both ways and see what works best.

Maybe this type of test doesn't work so well for that particular type of transistor, or maybe it is wrongly marked, I don't know, but that way to identify the pins usually works.

--
Roger J.
Reply to
Roger Johansson

Well -- you did qualify the claim that the transistor would work 'equally well', but the differences are very serious. For example, the collector breakdown voltage in reverse would likely be much much lower for most transsitors. Also, most discrete transistors have much lower beta in reverse (however, you can find some that have high beta in reverse, which can have significant effect on Vce saturation voltage.)

John

Reply to
John S. Dyson

I hope this clarifies the issue to "j van c" better than what I could give him.

Thanks.

--
Roger J.
Reply to
Roger Johansson

ElectronDepot website is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.