Probably wire loss E in volts.
L = length I = current CMA = wire cross-sectional area, circular mils K = fudge factor
2 = round tripJohn
Probably wire loss E in volts.
L = length I = current CMA = wire cross-sectional area, circular mils K = fudge factor
2 = round tripJohn
On Wed, 23 Mar 2005 20:38:00 GMT in sci.electronics.basics, "js5895" wrote msg :
See Gareth's answer, unless you don't know either E or I, in which case you cannot find the answer from the known information.
I have a question. What are K, C, M and A? I'm assuming this is a formula for the drop across an inductor, where E = I * XL, and XL =
2*Pi*f*L, so somehow Pi*f = K/(CMA)? Thanks.-- Al Brennan
Hi,
The voltage drop formula:
K x I x L x 2 E = ---------------- CMA
I know all the values, except "I", so is there a formula to find "I".
Thanks.
Are you saying that you know all the values in your equation except I, and you want to find I? If so that is simple algebra.
Multiply both sides of the equation by CMA:-
E x CMA = K x I x L x 2
Then divide both sides by K x L x 2:-
E x CMA
---------- = I K x L x 2
-- ----------------------------------------------------------------------- To reply to me directly: Replace privacy.net with: totalise DOT co DOT uk and replace me with gareth.harris
Thank You very much. If thats simple algebra, I don't know algebra, lol.
K = Approximate/Exact K of wire I = Current L = Length of wire, one way
2 = There and back E = Voltage drop CMA = Circular Mill Area of wireElectronDepot website is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.