Correcting for Impedance Errors w/o Superposition & FFT

If you already have the frequency response of the impedance of a circuit over a bandwidth, it should be possible to largely correct for differences in the reactance of a similar but less-than-perfectly- known circuit by applying a wave form which is a sum of one or several frequencies that fall within the known bandwidth.

Coefficients measured on the first circuit at the frequencies applied to the 2nd circuit are multiplied onto the response of the 2nd circuit.

If the phase angle is small, however, is may be possible to approximate the reactance another if somewhat less accurate way:

The first term would be some coefficient -- nothing to do with the coefficient above -- measured on the known circuit and multiplied by phi^2 ( i"/i').

Does phi^2 or i"/i' look familiar to anyone?

The phi term comes from knowing the difference between two sinusoidal curves separated by a small phase angle is close to the derivative of either curve times the phase angle.

Bret Cahill

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Bret Cahill
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Maybe just a phi^4.

The chances that this approximation hasn't already been done are just about nil.

Bret Cahill

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Bret Cahill

For a simple sinusoidal the first term is just proportional to phi.

Bret Cahill

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Bret Cahill

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