to paraphrase:
the problem with this is that only the PV array with the higher output current will contribute to the charging process.
i think in real life it depends on which parameter the arrays are most closely matched.
Real arrays behave like they have non-trivial internal resistance, so they if they procude similar voltages they can be paralleled and will share the load quite well.
An 'accident of fate'. It was a 50/50 chance. Doesn't seem to cause any trouble though unless you're dealing with device physics.
Graham
-- I think that would be true in the parallel case, where the PV with the highest voltage would cut the other one off by back-biasing its diode. In the series case, the current into the charger would be limited to the current available from the lower-current PV, but the voltage into it would be the sum of the PVs\' voltages, making the power into the charger greater than that available from either PV alone, I think.
-- Not true, since the current into the charger will be limited to what the _lower_ current PV array can supply. However, the _voltage_ into the charger will be the sum of the array output voltages, allowing the battery to be charged for a longer time until the charger\'s input voltage falls to the point where current can no longer be forced into the battery. JF
-- Not really, since one of Murphy\'s law states something like: "If you have a 50/50 chance of being right, 90% of the time you\'ll be wrong." JF
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