# coil gauge

• posted

HI again,

I read on the internet that depnding on the gaude size lets 18, it will take more amp to generate the same EM strenght as with a 30 gauge. considering there are the same weight of magnet wire to do the coil. I am not finding much information on this ( different gauge size Vs coil ) on the internet.

Ken

• posted

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The strength of the magnetic field will be determined by the number
of turns and the current in them, (Ampere-Turns) so the larger the```
• posted

Hi John,

Let me rephrase what i am trying to ask. The Magnetic field is H =N * I / L where N is the number of turn, I = current, L= lenght So, if I am making a coil and only have an inch of space to put my coil. I can use 18 Gauge or 30 gauge. I can wound 50 turns with the 18 Gauge and

100 turn with the 30 gauge. The smaller the wire, the less current I can put, but the more turn the more magnetic field I am creating. So basically I see that either way, I will end up with the same magnetic field. Therefore, just fill up the space with either gauge wire, I'll get the same weight, and by putting the maximum current capacity of the wire I get he same magnetic field. ???

Ken

• posted

As long as your are making air coils your can use

to calculate the coils.

• posted

Its not an air coil, but I'd like to know what are the formulas and how to use them .

ken

• posted

the strength is governed by the number of turns * the Amps. look up Webers, Gauss etc... if you use smaller gauge wire, you will need to factor in the resistance losses.

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Real Programmers Do things like this.
http://webpages.charter.net/jamie_5```
• posted

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18 AWG wire has a diameter of 0.0403", so you should be able to get:

1"```

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