XR2206 Waveform Generator

I'm not sure if anyone has built this circuit before

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The chip looks legit and simple. I have hooked up an exact circuit with exact parts on there. I have been able to see the square wave outputting at 0 to 12 V, and the frequency adjusts properly by adjusting R1 in the circuit diagram. However, I have trouble obtaining the sine wave signal as displayed on
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after playing around with the sine/triangular output switch and the THD and symmetry adjustment potentiometers. I have been getting a signal with a very small amplitude at best, with the frequencies that are not responsive to the frequency potentiometer. I'm not sure what went wrong there. I have hooked up everything correctly unless I have used inappropriate types of potentiometers (those that induces noise in the circuit?). Any comments on it would be appreciated.

Reply to
ssylee
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Does the triangle waveform work, or does it have the same problem as the sine wave?

Are you aware that the amplitude for the sine/triangle waveforms is much lower than for the square wave, and depends upon R3 (pin 3)? The datasheet specifies the output as typically 60mV/KOhm (min:max = 40:80).

If both triangle and sine exhibit the same problems, check the circuitry connected to pin 3. If triangle works but sine doesnt, check the switch and resistor between pins 13 and 14.

Reply to
Nobody

Hi,

I have supplied my circuit with 22 V. It appears that I'm only getting a triangular wave, even though I have looked at pins 13 and 14 (I could try changing the potentiometer there). The sine/triangular wave is about 10 V p-p with a few volts of offset from the ground. I have been able to vary R3 to change the amplitude to have the sine/ triangular wave max out at 10V p-p. Something is not right with the offset, although I'm not sure what I can do about it.

Cheers,

ssylee

Reply to
ssylee

For starters, there is no pot labelled THD. Second, try no load at output (10Meg scope probe is good enough approximation).

Reply to
Robert Baer

Hi Robert,

The THD pot I meant to point out refers to R3 on the diagram. Secondly, I looked at the output with no load at the output, although I don't know what's the impedance of my scope.

ssylee

Reply to
ssylee

R3 controls the triangle/sine amplitude. The THD control is the one between pins 13 and 14, labelled RA on the website (it's labelled "THD Adjust" in the data sheet).

Essentially, a lower resistance between pins 13 and 14 rounds off the top of the waveform. If pins 13 and 14 are open-circuit (S1 open), you get a triangle waveform. With a low resistance (S1 closed, RA in effect), the triangle peaks are rounded to give a sine wave (the sine wave should be roughly half the amplitude of the triangle wave for any given value of R3).

My first guess would be that either the IC is faulty or that closing the switch is causing a short between pins 13 and 14, pulling the peaks down to near zero rather than to only half the triangle amplitude.

Are you using the original schematic from page 2, or the version with more complex THD control shown on page 4 (and used for the PCB layout)? Have you made a PCB or is this on breadboard?

In any case, the first thing to check is whether pins 13 and 14 are being shorted when S1 is closed.

Reply to
Nobody

You damaged the chip? I looked up that chip number before. The output is suppose to be 6V p-p, either that was a miss print or, yours having that much output is in error! Make sure you have a by pass cap at the Vcc and ground (common). something like a .1 non electrolytic type. and maybe you should try another chip.

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Reply to
Jamie

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