1. Home
  2. Electronics Design
  3. Xmfr drive lo res load

Xmfr drive lo res load

This thing is driving me nuts. I have a TA2009 audio amp module. I want it to drive a PA type step-up transformer for voltage gain. IOW around 200V out. The signal is a 60Hz sinewave. The secondary is to be connected across a negligible load resistance, eg. wide area coil of few turns. But when I connect the latter, it kills the signal both sides of the xfmr.

Is there a right way to drive this coil via a xfmr or am I dreaming?

The module only does around 10W. Is this the problem? But I have tried adding 8 ohm resistors all over the place with no result.

Ken Donovan

Reply to
K. Donovan
Loading thread data ...

"K. Donovan"

** Why the heck are you surprised ?

What you are attempting is very silly indeed.

** Errrr - when you want to drive a load impedance that is LOWER than normal for an amplifier, the idea is to use STEP DOWN transformer.

Cos that will increase the available current while reducing the voltage by the same ratio.

Capice ?

........ Phil

Reply to
Phil Allison

Since it's 60Hz, you could try just plugging it into a mains outlet and see what happens. Likely, you'll blow a breaker; if not, the coil will probably get very hot. Current equals voltage divided by impedance. The impedance is probably quite low, a few ohms at most, unless the coil is really large, several square meters area and quite a few turns. Power dissipation equals square of current times resistance. Note that an 8 ohm resistor across 200 volts will dissipate (for a short time, at least) 5000 watts.

Just what is it that you are trying to accomplish?

Cheers, Tom

Reply to
Tom Bruhns

ElectronDepot website is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.