I don't know how you got the transposed equation, so I can't verify that.
But I like a different function to fit temperature to divider voltage that has a natural shape that is about right.
If you treat the A/D full scale value as 1, then you can convert the fraction of 1 (called f) to temperature (with a maximum error of about .7 degrees) by this formula:
Temperature= a * (tan(f - b) + c + d*f Where a=-240.5856, b=0.5515, c=123.0738, d=-102.1026
But if you change the series resistor to 24k, The worst case error is about half as big (about +-0.3 degrees) with these constants: a=-196.0598, b=0.5532, c=106.3374, d=-96.91