Optoelectronics question

Jan 27, 2016 43 Replies

Yes, if you use a silicon solar cell then a 950nm LED would be better than white or blue.

As long as the photons have enough energy to be received by the solar cell, any extra energy in the photons (more blue-ness) is wasted, yet it requires more voltage drop in the LED to create these bluer photons.

So a 950nm LED and a silicon solar cell or photodiode would be a good combination, which you can even buy in a DIP package. Some of them have many photodiodes in series as they are intended for driving the gates of MOSFETs, and can produce > 5 Volts.

This one can provide 7 Volts open-circuit and 12 or 20uA short-circuit:

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At the maximum-power point, it will produce slightly less than the short-circuit current, but if you shunt-regulate it to significantly lower voltage e.g. 3.3V or maybe even 5V then it will produce pretty much the short-circuit current.

The efficiency is not good, but it is not as bad as it seems from just looking at the current in and out, since the input voltage is 1.4V so it is stepping up the voltage.

If you don't want to use one of those opto-couplers and you don't want to use many photodiodes in series, and if you get to control the blinking of the LED, then it might make sense to modulate the LED at ~

100kHz, ~ 30% duty cycle, and feed the output from the photodiode straight into a step-up transformer or flyback inductor, and then rectify it. This would avoid any losses in a switching transistor (let alone gate drive generation) in the circuit connected to the photodiode that only provides about 0.6V

Chris

not necessarily equal, just "sufficient". equal will be most efficient though.

\_(?)_

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Interesting. The power this will maximally give would be about

0.75 * 8 V * 20 uA = 120 uW. 0.75 is a maximum power point (MPP) open voltage factor.

The advantage of the MPP is that you get the maximum power.

120 uW / 1.7 V * 10 mA = 120 uW / 17 mW = 3/4 % (more or less).

And if one would use one of those 200 uW/Mhz microprocessors, 2 of these opto-couples in parallel would do the trick.

Interesting thought, although the free-wheeling diode (also 0.6 V) would dissipate about 50% of the power if my intuition doesn't fool me.

joe

I strung a bunch of those together to try and make a ~100V supply. It was ok, but only as strong (current wise) as it's weakest link.

If you look at the numbers you might assume 10-15 photodiodes in series, and so ~1% of the LED current is captured.

George H.

One bad apple will destroy the whole chain.

Define "equal" please.

John Larkin Highland Technology, Inc lunatic fringe electronics

Is it possible to use a photo transistor as a compact solar cell? How's it work (other than "pretty good" or "real bad")....

Don't have any experience with that.

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Yes, but the output will be really tiny.

John Larkin Highland Technology, Inc lunatic fringe electronics

On Thu, 28 Jan 2016 08:22:01 -0800, John Larkin Gave us:

Probably get more from a resistor bolometer package.

Except that resistors don't generate power like solar cells do.

John Larkin Highland Technology, Inc lunatic fringe electronics

Den torsdag den 28. januar 2016 kl. 17.12.36 UTC+1 skrev bitrex:

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-Lasse

Not if it only has two leads. You can think of a phototransistor as being a normal NPN with a very small photodiode connected from base to collector. (It's actually the collector depletion region that does most of the photodetecting.)

If the base lead is brought out, you can get the photocurrent by connecting C and B to the external circuit, but you'll be very disappointed by how much you get.

If all you have is C and E, then there's a reverse-biased junction in series with the photocurrent, so you don't get any out. Putting the transistor in normal bias lets it work, of course.

Cheers

Phil Hobbs

Dr Philip C D Hobbs Principal Consultant ElectroOptical Innovations LLC Optics, Electro-optics, Photonics, Analog Electronics 160 North State Road #203 Briarcliff Manor NY 10510 hobbs at electrooptical dot net http://electrooptical.net

The worst cell defines the maximum string current, so the best interest is to illuminate the cells evenly.

Nice, thanks for the explanation.

Do they make really tiny solar cells, then? Say, not much larger than the diameter of the LED. Probably not much demand for that.

Circuit would need to be very compact.

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Yeah.... they are called photodiodes. :^)

George H.

On Thu, 28 Jan 2016 13:23:43 -0800 (PST), George Herold Gave us:

Chop, chop, old chap.

:-(((((((

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That's what's inside a PV optocoupler, or inside an SSR.

John Larkin Highland Technology, Inc picosecond timing precision measurement jlarkin att highlandtechnology dott com http://www.highlandtechnology.com

What about a PIN photodiode? Area is about 1 cm^2 (or should that be pF^2 :)

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joe

Yeah, BPW34 off eBay.

Beware of Electronic Goldmine "FPT 5086 Photodiode (Pkg of 4)" which is actually a phototransistor. I think "FPT" means "Fairchild PT"

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