Precisely. However I am more interested in the opposite trick: if a small resistor is bootstrapped by a low noise amplifier with the gain close to unity, the input impeadance is multiplied while retaining the voltage noise of the small resistor.
Yes. The simple math shows that it is possible to reduce the noise temperature by about of the order of magnitude.
It works, although there are some pitfalls because of the phase shifts and the stability concerns.
They basically do the same thing plus the C1/C2 transformer feedback coupling. This allows for the additional flexibility, not sure about the stability margin though.
Vladimir Vassilevsky DSP and Mixed Signal Design Consultant