I think that is a microwave oven stunt.
Just the same i saw an SPG-51 with the illuminator on drop=20 a seagull out of the air at about 100 feet. Maybe 100 ms=20 time within the beam. Still a freak chance. Tracking radar=20 portion 50 kW and illuminator an additional 50 kW. Pumped=20 klystron outputs.
Easy, this will burn out front ends 10 to 20 miles out or more;
Was this the same friend that was killed by a speeding driver?
And what do you propose to do regarding the aperture efficiency? I would not (necessarily) assume that the field would be uniformly absorbed by the "front end". I agree that it's a trivial matter to calculate the equivalent electric field density at the front end, but that field must still be intercepted by something - to do any damage.
Friis is the classic equation for the transfer of power between two antennas, and thus, if you treat the "front end" as an antenna, then there you have it. Perhaps we may disagree on whether it is appropriate to treat the "front end" as an antenna, but that's sounds like a separate discussion...
I don't want to get into a pissing contest over it.., but I do think the question about the destructive capability of radiofrequency energy must at least consider the transfer efficiency and/or the absorption of the field. In short, knowing the RF illumination at the front end does not tell you how much power is being dissipated -- rather, how much power is "available" to be dissipated. Assuming of course, that we are in the far field, that the fields are in quadrature, etc...
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