Luxeon 5W

From the data sheet, 700 mA at 6.84V typical is 4.788W typical.

Is the 2 watt number the output? 100W light bulbs are rated byt the power they consume, not the visible light they radiate.

I was looking at another electrical drive sheet, and it said 350 ma.@ 6 volts. Thats input power. The 5W led is four times as bright as the 1W series.

greg

I have some work to do to find the best way to sink these things, as I need to get 9 LED's in very close proximity. I'm thinking copper with a 100um layer of insulation. Some kind of epoxy painy? I'm also considering glueing the LED emitters directly to copper rods which will terminate into another block of copper or aluminum.

greg

That partnumber isn't on my datasheet. Many of the 5-watt Luxeons have typical Vf of 6.82v at rated 700 mA and 25C, which is 4.48 watts.

If you use Stars, the heatsink is electrically neutral so they can go directly on the heatsink. Use heatsink grease. With emitters, secure them with a good thermal epoxy like Omegabond 101. In either case, your heatsink is going to need enough area or forced air cooling or both to keep the sink at acceptable temperature while dissipating

45 watts or so. Check their website for app notes on thermal management and maximum acceptable package operating temperatures.

AB23: Thermal Design Considerations for Luxeon V Power Light Sources

The Luxeon V takes 700mA drive @ roughly 7V, as John_H commented above.

FYI, the early white Luxeon V--now called the Luxeon V Portable-- was only rated for 500hrs operation rather than 100,000hrs. I don't know if this has changed.

James Arthur

The emitter heat surface is electrically active, so each emitter must be isolated from each other.

greg

I'm more interested in the use of heat spreaders such as:

Which provide the opportunity to move the heat to a larger heatsink area around the LEDs.