I am building an experimental vertical aerial of the 'colinear' type for the 2-metre amateur band (144 to 146 Mc/s in the UK).
It consists of a quarter wave whip at the top with four dipoles vertically below it. Each dipole is made of 50-ohm co-ax and the connections between the inner and the screen are transposed at each junction. It is connected to the feeder by a choke that blocks any common-mode component.
The whip is actually just below a quarter-wavelength to allow for the end effect. The dipole sections are considerably shorter than a half-wavelength to allow for the velocity ratio of the co-ax, which was measured at 0.65.
If the reversals are ignored, the impedance at the junction of the whip with the top dipole is about 50 ohms. The impedance will again be 50 ohms half a wavelength below that and similarly 50 ohms at each junction point. The reversals are there to ensure that the radiating conductors which are exposed to the outside world are always in the same polarity as each other, so the radiation pattern is nearer horizontal.
If there were no reversals, the dipoles would simply act as lengths of co-axial feeder and the impedance at the bottom of the bottom dipole should be 50 ohms. The reversals are supposed to make the dipoles radiate energy, so a resistive component (radiation resistance) is introduced into the 'feeder' to the whip. You can't get something for nothing, so the energy radiated by the dipoles has to come from the transmitter in some way.
My question is: Are these extra radiating resistances of the dipoles in series or in parallel with the radiating resistance of the whip? Is the impedance at the bottom of the bottom dipole 50 ohms - or lower - or higher?
I am about to test this but I would be interested to know if anyone already has the answer and what line of thought led them to it.