How to make an 8mH inductor which can handle 13V peak square wave without saturation

I used to know all this many years ago... how to work out the flux density, and choose a material which doesn't saturate, but I have long forgotten!

It needs to be good with a 13V peak square wave, 500Hz.

So we have 13V across 8mH for 1ms, which from v = L (di/dt) yields

1.625A. A quick hack in LTspice confirms this, for the first 5 cycles. I had a lot of trouble generating a square wave from -13V to +13V :) so I am not sure what the current waveform will look like when you switch to -13V when the current flowing is still 1.625A; I suspect it will not ever exceed 1.625A later though. With a 13V peak sinewave (a predefined function in LTspice) it looked to be just under 1A, but all positive which is obviously BS.

The bit I have forgotten is how to calculate the flux density in the core. I would prefer the whole thing to be something the size of an RM10 core

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3C95 material you have 5500nH/T^2.

A toroid would have less stray flux, and again there is a vast choice. I have a bag of these from many years ago

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with 83 turns would achieve 8mH.

What I don't get is how much current this will carry. 83 turns at 1.6A is 132 AT which sounds an awful lot. I thus suspect I will need a bigger core, probably iron.

Looking on Ebay for ready made stuff, 10mH, I see e.g.

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I am instinctively damn sure that won't carry the current.

Another option is some toroidal transformer, and ignore the existing winding and put more turns on it. Ebay is full of vintage transformers but most are pretty big.

I was going to wind the TN16 with some turns and see what it does. I have an HP 3314 pulse generator and a power amp which can output 9V peak.

The 8mH needs to be +/- 0.3mH. It was determined experimentally using this amazing thing

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that obviously contains massive magnetics - it weighs about 1kg.

I also have an LCR meter.

I'd be grateful for any suggestions.

Reply to
Peter
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John Larkin snipped-for-privacy@997PotHill.com wrote

It is to reduce the output from an LVDT, by putting this in series with the input. The reason for reducing the output is a bit obscure...

Reply to
Peter

We do a lot of LVDT measurement and simulation, usually at higher frequency but occasionally at 400 Hz.

You could use a step-down transformer instead of a series inductor, for less phase shift and better linearity and a predictable ratio. Some little audio transformer.

Ir maybe a resistive voltage divider.

Reply to
john larkin

Don't be surprised. It's common to have to brush up on basics, if you don't use them regularly.

Your AC source is seen by the sim to have the polarity of the first

  • pulse. The -pulse that follows can only return mag current to zero, hence a net +DC can show up in early portions of the sim. Ad a load to get AC-only current, eventually.

RM10 DC saturation current will depend on turns count and gap. Saturation flux in ferrite is ~0.33T.

B = u N I / lm

B = flux density in Teslas u = 4.pi.E-7 N = turns count I = current in Amps lm = magnetic path length (or gap width, if present) in meters.

For pulsed DC

deltsB = V T / N Ae

deltaB = flux density change in Teslas V = applied volts in Volts T = time in seconds N = turns count Ae = cross-sectional area of flux path im meters^2

inductance of gapped structure

L = 4.pi.E-7 N^2 Ae / lg

L = inductance in Henries N = turns count Ae = cross-sectional area of flux path im meters^2 lg = gap width in meters

Solutions will depend on whether or not you intend to use the part in AC-only, small signal situations, or whether the part is intended to do some work in a resonant power or filter circuit.

Check what's on offer in distributors' catalogs. This will give you a ball park idea of the size and shape of stuff you'll be aiming for and may offer a simple solution off the shelf.

RL

Reply to
legg

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It would be easier to help if you stated the application and known limits/requirements of size, weight, mounting method, environment etc.

'carry the current' really doesn't tell us anything.

If there are 'found' materials you'd prefer to use . . . and results from your attempts to do so.

etc.

RL

Reply to
legg
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I see no reference to an LVDT application in the Peter's posting.

RL

Reply to
legg

It is an instrument which contains an LVDT bent into a half circle, to return an angle.

It is excited with 500Hz, and it is pretty well a square wave. I didn't design that bit :) And the output is too high, for reasons too complex to explain. So I need to reduce the output somehow.

Reply to
Peter

Not on this reader. I have only:

Tue, 30 Jan 2024 16:13:41

RL

Reply to
legg

So you've got 500Hz @ 13V (pk?). and you can't adjust the source (why not?)

AC or DC?

You could reduce the output phase width with a saturable reactor.

For pulsating DC, it might be a regulated 'set' reactor.

For AC, it could be a bit more complicated, unless you were satisfied with just a fixed PW blocker. That might drift a bit with load or temperature. Gets physically bigger the more voltseconds you want to block, for the same current.

The 'complicated' saturable reactor for AC begins to look like a mag amp.

RL

Reply to
legg

Anyhow, he said he wanted to reduce the drive level into an LVDT.

I think he could use a simple LC or RLC to make a nice lower-amplitude sine from his big square wave.

Reply to
john larkin

It would make more sense to excite it with a lower amplitude sine wave. The angle sensing differential transformer will run cooler - those higher harmonics generate extra heat in the core material.

It's a bigger change than your boss had in mind, but would give you an appreciably better system.

Reply to
Bill Sloman

About LVDTs, I know nada.

RL

Reply to
legg
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...but nowhere near enough current. Ferroxcube have (or had) a free downloadable calculator.

As you have already some cores, you could stack several into a tube shape. I've done this where the available space made it the only game in town. Tricky to wind but fun, FSVO 'fun'.

Reply to
Clive Arthur
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Depends how the demodulation works, it's often synched to the drive signal and there may be no phase adjustment.

Reply to
Clive Arthur

Yeah, there are a host of things I could fiddle with, but I like to keep my distractions at least vaguely on track.

RL

Reply to
legg

If you can scope a current waveform, you might get an idea of what the most troublesome harmonics are, then see if a simple LC filter will help. You'll need the C for any L to work.

RL

Reply to
legg

Probably, but the OP didn't specify the application. LVDTs can be

*very* long - the materials testing machines I worked on often used short stroke LVDTs for test coupon strain measurement and long stroke - 0.5m - for clamp positioning, but in some applications much longer devices can be used.

I'm assuming the OP has tried an 8mH inductor, is happy with the result, and doesn't want any more complication.

Reply to
Clive Arthur

It's not a good idea to excite an LVDT with a square wave. The OP should set up a circuit to provide a stable sine wave of the right amplitude, rather than waste time trying to cut down the amplitude of the square wave with temperature dependent voltage drops through diodes.

Reply to
Bill Sloman

The next tme that Russia or France or Germany wants to invade your tiny damp country, we'll sit it out.

Reply to
john larkin

That is exactly what I did.

I bought a 0-10mH (in 1mH steps) variable inductor off Ebay and found

8mH does the perfect job. General Radio 940
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Got this from Mouser and will test it
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The 1.6 amps is real, give or take a bit. Yesit surprises me it is that much. But I can't change the drive circuit. It's simply crap. Honeywell, BTW ;) Well, actually, from the last days of Bendix King, around 24 years ago.
Reply to
Peter

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