hip
-gher
out
do
s two
8 x _ sI use the rule that if it is full wave, you always need half again as many VA as you hope to get in Watts out.
If it is half wave, you need about double that number.
hip
-gher
out
do
s two
8 x _ sI use the rule that if it is full wave, you always need half again as many VA as you hope to get in Watts out.
If it is half wave, you need about double that number.
Cool, It's going to take me a bit to follow all the currents in that circuit. Are the >! ,in the center of each bridge, diodes from the DC voltages to ground?
Does this have a name? (Just thought I might find a schematic on the web with more details.)
The number came (to me) from a transformer manufacturer, but has also been quoted in the RS catalogue (print - I don't know about on-line) and the Altronics catalogue. Not definitive sources I grant you. I should have mentioned that it applied to a capacitor filtered power supply. Vmax = 2.82 x Vac(rms) and Imax = .38 x Iac(rms).
However. seeing that my brain is stuffed (the reason I retired) there may be "some" error there - just checking a catalogue and it says .28 .
r
The >! is just to show which way all the diodes in the bridge are pointing. The cathodes are all on the end more towards the right.
It is just another version of the voltage doubler.
No need to match the diodes, but you need twice the PIV rating of the diode for a full bridge.
mkr5000
=20
Well one end of the transformer is connected only to capacitors, how do you get a DC current in the transformer?
Have something to add? Share your thoughts — no account required.
Ask the community — no account required